hope it helps u..........
Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer: it’s -2,-4
Step-by-step explanation: since the dilation rule is 2/3 we take 2/3 of all the numbers. For example we took two thirds of -3 to get -2.
Answer: The product of 3. 5 and a number is greater than or equal to 7.
Step-by-step explanation:
Answer: I think it it 5 if
Step-by-step explanation:
If I am wrong I am very sorry and if I am right could you please make me brainliest please?
