Your first step would be to unsolve the zeros, which would leave you with x-1, x-1, and x+2. Then arrange the zeros in the position of a factored polynomial, such as (x-1)(x-1)(x+2), and then FOIL the first two terms. You would then end up with, x^2-2x+1(x+2). After this just finish unfactoring the polynomial.
Your answer would be:
1x^3+0x^2+-3x+2
Answer:
Subtract 2 from the term number
Step-by-step explanation:
Answer:
Step-by-step explanation:
<em>(5√3*√3)+(5√3*5)+(-1*√3)+(-1*5) </em>
<em>5*3+25√3-√3-5 </em>
<em>15+24√3-5 </em>
<em>**24√3+10** </em>
<em></em>
<em>Then to solve the second, apply division rules within the radical. This means you can cancel an m^1 and n^4 from the bottom and top of the fraction. This leaves... </em>
<em>3√(88m^19*n^8) </em>
<em>(That might be all you need to do, otherwise you can take the square root of each number in the term giving... </em>
<em>3(√88)*m^9.5*n^4)</em>
<em></em>
<em>Hope I made it clear enough</em>
<em></em>
<em>Please give me Brainliest</em>
Answer:
√109
Step-by-step explanation:
3^2 + 10^2 = c^2
9 + 100 = 109^2
Answer:
6
Step-by-step explanation:
Typically these kinds of problems are solved using Venn Diagram.
Let’s solve it differently.
Here, we add the individual subject students and subtract the dual subject students and then add the triple subject students that would give us the count of all the students. If that’s more than number of students then there’s something wrong with the given data. If that’s exactly equal to number of students then all the students have taken some course(s) or the other. If that’s less than number of students then subtracting this from number of students would give us the count of students having not taken any course(s).
Thus, the count of students having taken some courses or the other is:
20+18+16–7–7–9+3 = 57–23
= 34
Subtracting it from 40 gives us 6, which is the count of students not taking any course(s).
Please mark brainliest if possible and have a nice day. :)
