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2 years ago

Calculator display for 1/9

Mathematics

2 answers:

vitfil [10]2 years ago

7 0

Answer:

Here ya go :)

Step-by-step explanation:

Hope this helps!

Have a nice day <3

KIM [24]2 years ago

5 0

1/9 on a calculator is 0.11111111

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I need help with this question

Delvig [45]

Answer:

Go download CameraMath on playstore that how

I is get my answer

4 0

2 years ago

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

2 years ago

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

mote1985 [20]

The confidence interval for the mean usage of water is (18.7,20.5).

Given population standard deviation of 2.4, mean of 19.5 gallons per day and confidence interval of 98%.

We have to find the confidence interval for the mean usage of water.

To find out the confidence interval we have to first find margin of error.

μ=19.5

σ=2.4

α=0.98

α/2=0.49

We have to find the z value for the p value 0.49 which is z=2.33

Margin of error=z*μ/ $\sqrt{n}$

=2.33*19.5/ $\sqrt{3034}$

=0.82

lower level=mean -m

=19.5-0.82

=18.68

after rounding upto 1 decimal

=18.7

upper mean = mean+m

=19.5+0.82

=20.52

Hence the confidence interval for the usage of water is (18.7,20.52).

Learn more about margin of error at brainly.com/question/10218601

#SPJ4

7 0

1 year ago

One lap around the lake is 7/10 mile Dasha runs 9 laps around the lake

Sindrei [870]

Answer:

6.3

Step-by-step explanation: Divide 7 by 10 and get .7 then you would multiply that by 9 and youll get 6.3

4 0

3 years ago

Mercury has a density of 13.6 g/mL. A sample of mercury weighs 2.25 kg. What volume does it occupy

laila [671]

Answer:

165 mL

Step-by-step explanation:

Density is mass divided by volume:

D = M / V

Solving for volume:

V = M / D

The density is given in g/mL. So first let's convert the mass from kg to g:

2.25 kg × (1000 g / kg) = 2250 g

Plugging in values:

V = (2250 g) / (13.6 g/mL)

V = 165.4 mL

Rounded to 3 significant figures, the volume is 165 mL.

8 0

3 years ago