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balandron [24]
2 years ago
10

Madeline uses 58 beads to make a necklace she plans to sell 36 necklaces at each craft fair she goes to the summer she plans to

go to for craft fairs this summer what is the total number of speeds that Madeline will use to make the necklaces she plans to sell at the for craft fairs show your work
Mathematics
1 answer:
g100num [7]2 years ago
5 0
<h3>♫ :::::::::::::::::::::::::::::: // Hello There ! //  :::::::::::::::::::::::::::::: ♫</h3>

➷  Multiply the number of beads per necklace by the number of necklaces:

58 x 36 = 2088

This is the number of beads needed per each craft fair.

Multiply this value by 4 to get the final value:

2088 x 4 = 8352.

She will need 8352 beads.

<h3><u>❄️</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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1!<br><br><br><br><br> please help!!<br><br><br> math geniuses where r uuuu<br><br><br><br> help!
Serhud [2]

Answer:

i think option d tan theta =0

3 0
2 years ago
a mower uses 5/16 gallon of gas to mow the back yard. the side yard is only 2/3 the size of the backyard. How much gas will be n
Trava [24]

Answer:

(5/24) gallons of gas to mow the side yard

Step-by-step explanation:

We can easily solve this proble by applying a rule of three

5/16 gallons of gas  ---------------------------------  for 1 backyard

x  gallons of gas ------------------------------------- 2/3 backyard

x = ((2/3)/1)*(5/16) gallons of gas

x = ((2/3))*(5/16) gallons of gas

x = ((10/48) gallons of gas

x = (5/24) gallons of gas

3 0
3 years ago
SOMEONE HELP I WILL GIVE BRAINLIEST 6TH GRADE MATH
jasenka [17]

Answer:

1. 15%

2. 85%

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The graph is 100 units,

the shaded part is 15 units,

so it is 15%,

if it is 15% than the unshaded part is 85%.

3 0
3 years ago
Identify which number is between -3.5 and -3.7?<br>A.-3.74<br>B.-3.69<br>C.-3.12<br>D.-3.18​
Degger [83]
D is the answer because it’s between -3.5 and -3.7
4 0
3 years ago
Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x&lt;-36
Oliga [24]
X²+15x+36<0

at first solve quadratic equation

D=b²-4ac= 225-4*1*36= 81

x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
 1 case)      x+12<0, and x+3>0,                                            
                       x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set

or second case)  x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3)  they are crossing , so (-12, -3)  is a solution of this inequality


3 0
3 years ago
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