Ask question

Ask question

All categories

3 years ago

13

X-2=144Find all complex number solutions

1 answer:

cupoosta [38]3 years ago

7 0

Hey!

To start solving for x you'd need to add two to both sides of the equation. This will give us the variable, x, on its own.

Original Equation :
x - 2 = 144

New Equation {Added Plus Both Sides by Two} :
x - 2 + 2 = 144 + 2

Solutions {New Equation Solved} :
x = 146

So, since the answer can be simplified no longer, our final answer is x = 146.

Hope this helps!

— Lindsey Frazier ♥️

You might be interested in

How many 3/4 foot pieces of string can be cut from a piece of string 4 1/2 feet long

Gnom [1K]

3/4 foot is 9 inches, and 4 1/2 feet is 54 inches, so, 54/9 makes exactly 6 pieces of string.

8 0

2 years ago

When you buy the bond the exchange rate is $1.50 = pound1. You pay pound45 ($67.50) for the British bond. You sell the bond

natka813 [3]

Answer:

The gain is of $17.50

Step-by-step explanation:

When you buy the bond the exchange rate is $1.50 = £1.

You pay £45 = $1.50\times45$ =$67.50 for the British bond.

No, you sell the bond for £50 and the exchange rate is $1.70 = £1.

So, you earned $50\times1.70=85$ dollars

Your gain is $85-67.50$ = $17.50

3 0

3 years ago

PLEASE I REALLY NEED HELP

vovangra [49]

Answer:

who think

Step-by-step explanation:

5 0

2 years ago

In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the

Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

$(AB)^2=(BC)^2+(AC)^2$

$(13)^2=(BC)^2+(5)^2$

$169=(BC)^2+25$

$BC=12$

$\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\sin A=\frac{BC}{AB}$

$A=\sin ^{-1}\frac{12}{13}$

$A=67.38$

Bisector divides the angle in two equal parts, therefore,

$A'=\frac{67.38}{2} =33.69$

In triangle ACD.

$\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}$

$\cos A'=\frac{AC}{AD}$

$\cos (33.69^{\circ})=\frac{5}{AD}$

$0.832=\frac{5}{AD}$

$AD=\frac{5}{0.832} =6.009\approx 6.01$

Therefore the length of the angle bisector of angle ∠A is 6.01.

4 0

3 years ago

Divide 30 in a ratio of 3:2

pogonyaev

3+2=5
30 divided by 5=6
6X3=18
6X2=12
18+12=30
18:12

5 0

3 years ago

Read 2 more answers