Let say radius is r
<span>its height is h </span>
<span>its lateral area = y </span>
<span>y = 2 pi r h </span>
<span>since the cylinder is inscribed in the sphere </span>
<span>So (2r )^2 + h^2 = 64 </span>
<span>then 4 (r^2) = 64 - h^2 </span>
<span>since y^2 = 4 (pi)^2 r^2 h^2 </span>
<span>then y^2 = (pi)^2 *h^2 * (64 -h^2) </span>
<span>y^2 = 64 (pi)^2 * h^2 - (pi)^2 * h^4 </span>
<span>2 y y' = 128 (pi)^2 * h - 4 (pi)^2 * h^3 </span>
<span>putting y' = 0 </span>
<span>4 (pi)^2 h ( 32 - h^2)=0 </span>
<span>ether h = 0 testing this value (changing of the sign of y' before and after ) y is minimum </span>
<span>or h = 4 sqrt(2) </span>
<span>testing this value (changing of the sign of y' before and after ) y is maximum </span>
<span>So the maximum value of y^2 = (pi)^2 *32 *( 64 - 32) </span>
<span>y^2 = (pi)^2 * (32)^2 </span>
<span>y = 32 (pi) square feet
hope this helps</span>
Mean absolute deviation is the average of the sum of all deviations of the terms from the average of the terms...
mean=(5+9+9+11+16)/5=10
mad=[(10-5)+(10-9)+(10-9)+(11-10)+(16-10)]/5=2.8
Acceleration is the change in velocity, so if there is zero acceleration, the ball's speed and direction are constant. Therefore, the only plausible answer to our question is B. This is because the ball's speed stays the same, and its direction is also constant.
Answer:
IQR: is the length of the middle 50% of that interval of space
Step-by-step explanation:
In order to find IQR, subtract the third interquartile range - the first interquartile range
Answer:
65
Step-by-step explanation:
