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ycow [4]
3 years ago
12

How do you write y - 2 = (x + 3) in slope intercept form?

Mathematics
1 answer:
Sliva [168]3 years ago
3 0
Y - 2 = x + 3
  + 2      +  2
     y = x + 5
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Question 8 (1 point)<br> Find the perimeter of the triangle.
Romashka [77]

Answer:

D

Step-by-step explanation:

its the closest to the answer i got so that must be it

6 0
2 years ago
The supplement of an angle is three times the measure of the angle.
stira [4]

Answer: The angle equals  45 ∘  and the supplement is  135 ∘

Explanation:

Since the supplement is three times the angle, we can say    s  =  3 a

Since we know the supplement is  

180 − a , we can plug that in.

180 - a = 3a

180  = 4 a  (add  a  to both sides)

45  =  a  (divide both sides by  4)

Since we know the angle now, all we have to do is multiply it times  3  to find the supplement.

45  ×  3  =  135

4 0
3 years ago
At a university, 60​% of the students who apply. Of the students the university​ accepts, 25% actually enroll If 2000 students​
sweet-ann [11.9K]

Answer:

300 students are enrolled.

Step-by-step explanation:

As the university accepts 60% of the students who apply.

As 2000 students apply, it means that:

2000 × 60% ⇒ 2000 × 0.6 = 1200 students are accepted

Out of these 1200, 25% enrolled

1200 × 25% ⇒ 1200 × 0.25 = 300 students are enrolled

Therefore, 300 students are enrolled.

5 0
3 years ago
What is 40 percent of 50
valentinak56 [21]
20 is the answer to the question you asked.
3 0
3 years ago
Read 2 more answers
The mean percentange of a population of people eating out at least once a week is 57℅
Sidana [21]

Answer:

<u>The correct answer is B. between 56.45% and 57.55% </u>

Complete statement and question:

The mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.50%. Assume that a sample size of 40 people was surveyed from the population a significant number of times. In which interval will 68% of the sample means occur?

between 55.89% and 58.11%

between 56.45% and 57.55%

between 56.54% and 57.46%

between 56.07% and 57.93%

Source: brainly.com/question/1068489

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean percentage of a population of people eating out at least once a week  = 57%

Standard deviation = 3.5%

Sample size = 40

Confidence level = 68%

2. In which interval will 68% of the sample means occur?

For answering this question, we should find out the standard deviation of the sample, using this formula:

Standard deviation of the sample = Standard deviation of the population/√Sample size

Standard deviation of the sample = 3.5/√40

Standard deviation of the sample = 3.5/6.32

Standard deviation of the sample = 0.55

Let's recall that a confidence level of 68% means that 68% of the sample data would have a value between the mean - 1 time the standard deviation of the sample and the mean  + 1 time the standard deviation of the sample. Thus:

57 - 1 * 0.55 = 57 - 0.55 = 56.45

57 + 1  * 0.55 = 57 + 0.55 = 57.55

<u>The correct answer is B. between 56.45% and 57.55% </u>

7 0
3 years ago
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