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3 years ago

The _______ reimburses the dealership for warranty repairs. A. customer B. service manager C. shop owner D. manufacturer

Advanced Placement (AP)

2 answers:

nataly862011 [7]3 years ago

7 0

I think it’ll be D.

kramer3 years ago

3 0

Answer:

D. manufacturer

Explanation:

Defect in the newly purchased car. Inconvenient, of course, but it can happen to anyone who planned the purchase carefully. To minimize the client's headache, the consortium offers contractual warranties that entitle you to free repairs for a specified period. The problem is that these repairs can be a great damage to the repair companies, especially when the defect comes from the factory. For this reason, it is mandatory that in certain cases the manufacturer reimburse the dealership for warranty repairs.

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The graph of f(x) = 1/x cos

nikitadnepr [17]

Answer:

D. f(x) exist for all real numbers where x ≤ -1 or x ≥ 1

Explanation:

You can't divide by 0 and

You can't have a negative squareroot.

So solve for when x=0 for the denominator,

and when is x<0 for the squareroot.

4 0

3 years ago

1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The

Arlecino [84]

Hi there!

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

$\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt$

Evaluate using a calculator:

$= 899.97 \approx \boxed{900\text{ people}}$

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
$\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt$

We can evaluate using a calculator (math-9 on T1-84):

$\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt$

$= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}$

If:
$P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt$

Then:

$\frac{dP}{dt} = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt = S(t) - R(t)$

Evaluate at t = 20:

$S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669$

$S(20) - R(20) = 87.844 - 108.669 = -20.823$

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

$80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0$

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0

2 years ago

Which of the following will NOT protect against brief exposure to dangerous gases or fumes?

Svetlanka [38]

Answer: supplied air mask

Explanation: because air can go in the mask and the gases and fumes can hurt you.

4 0

3 years ago

Being a thief is deviant. True or False

nika2105 [10]

I would say true? ☺ Hope this helps

4 0

3 years ago

In ____, distant objects are seen clearly but close objects appear blurry; In___, close objects are seen clearly but distant obj

wariber [46]

first blank: farsightedness (hyperopia)

second blank: nearsightedness (myopia)

7 0

3 years ago