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Elza [17]
4 years ago
13

After all of the account balances have been extended to the Income Statement columns of the end-of-period spreadsheet, the total

s of the Debit and Credit columns are $77,500 and $83,900, respectively. What is the amount of the net income or net loss for the period?
Mathematics
1 answer:
Lana71 [14]4 years ago
6 0

Answer:

Net income = $6400

Step-by-step explanation:

As per the question,

Total debit columns after all of the account balances have been extended to the Income Statement columns of the end-of-period spreadsheet is given,

Total debit =  $77,500

Total credit columns after all of the account balances have been extended to the Income Statement columns of the end-of-period spreadsheet is given,

Total credit = $83,900

The amount of the net income or net loss for the period is given by

= Total credit - Total debit

= $83,900 - $77,500

= $6400

As the outcome is positive, it implies net income.

Hence, the required net income for the period = $6400

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3 years ago
The mean per capita income is 23,037 dollars per annum with a variance of 149,769. What is the probability that the sample mean
mihalych1998 [28]

Answer:

Probability that the sample mean would be less than 23,013 dollars is 0.2358.

Step-by-step explanation:

We are given that the mean per capita income is 23,037 dollars per annum with a variance of 149,769.

Also, a sample of 134 persons is randomly selected.

Firstly, Let \bar X = sample mean

The z-score probability distribution for sample mean is given by;

              Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean per capita income = 23,037 dollars p.a.

           \sigma = standard deviation = \sqrt{Variance} = \sqrt{149,769} = 387 dollars p.a

           n = sample of persons = 134

So, probability that the sample mean would be less than 23,013 dollars is given by = P(\bar X < 23,013 dollars)

      P(\bar X < 23,013) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{23,013-23,037}{\frac{387}{\sqrt{134} } } ) = P(Z < -0.72) = 1 - P(Z \leq 0.72)

                                                                    = 1 - 0.7642 = 0.2358

The above probability is calculated using the z-score table.

<em>Therefore, probability that the sample mean would be less than 23013 dollars if a sample of 134 persons is randomly selected is 0.2358.</em>

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A farmer wants to put a fence around a garden in the shape of a square. The fence posts are placed every 2 meters. One side of t
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Answer:

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Step-by-step explanation:

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3 years ago
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84,000/15 = 5600

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