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klemol [59]
4 years ago
15

How to make a number line

Mathematics
2 answers:
tester [92]4 years ago
3 0
  • Make a line _______________
  • then put little lines like this on it _/_/_/_/_/
  • Then put you numbers below the little lines
liubo4ka [24]4 years ago
3 0

first just draw a straight line , with arrows on both points on the line

then , on the line , take a distance of 1 cm and draw more smaller lines

mark the mid point as 0 and to the right write positive no.s like 1 2 3

and to the left write negative no.s like -1 -2 -3 ect .

i would like to attach a picture to make it more clear to u

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Ierofanga [76]
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ATTENTION
finlep [7]

Here!

<h2>The answer is Option A!</h2>

(x + 2 \sqrt{3} i)(x - 2 \sqrt{3}i )

<h3>Why so??</h3>

Let's see what complex numbers are!

(x + 2  \sqrt{3 }i  )(x - 2 \sqrt{3}i ) \\  =  {x}^{2}  - 2 \sqrt{3} x + 2 \sqrt{3} x -  {(2 \sqrt{3} i)}^{2}  \\  =  {x}^{2}  -  {(2 \sqrt{3}i) }^{2}

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And thus we get the answer!

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lbvjy [14]
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4 0
4 years ago
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Find the volume of this sphere.<br> Use 3 for TT.
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3 years ago
A 1125 ft^3 open-top rectangular tank with a square base x ft on a side and y ft deep is to be built with its top lush with the
nikdorinn [45]

Answer:

The values of x and y that will minimize the cost is 15 ft and 5 ft respectively and the minimum cost will 3,375

Step-by-step explanation:

With a 1125 ft^3 open-top rectangular tank with a square base x ft on a side and y ft deep is to be built with its top lush with the ground to catch runoff water, x is the length, y is the height;

x^2*y = 1125

y = 1125/x^2 ----(1)

The total cost of c = 5(x^2 + 4xy) + 10xy

Then,

c = 5(x^2 + 4x*(1125/x^2)} + 10x*(1125/x^2)

c = 5x^2 + 22,500/x + 11,250/x

c = 5x^2 + 33,750/x

To minimize the cost of c, find the derivatives of c; c'

c' = 10x - 33,750/x^2

c' = (10x^3 - 33,750)/x^2

c'(x) = 0; 10x^3 = 33,750

x = ³√33,750 = 15

x = 15; y = 1125/x^2

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(x,y) = (15,5)

c = 5x^2 + 33,750/x

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The values of x and y that will minimize it is 15 ft and 5 ft respectively and the minimum cost will 3,375

8 0
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