The missing value of the solution to the equation y = −2x + 4, is: 3.
<h3>What is the Solution to an Equation?</h3>
The solution to a given equation, is the x and y values of an ordered pair that would make the equation true, if we substitute their values into the equation.
Given the equation, y = -2x + 4, and we have (x, -2) as the solution where the value of x is the missing value in the solution, to find the value of x, substitute y = -2 into the equation and solve for x:
-2 = -2x + 4
Subtract 4 from both sides
-2 - 4 = -2x + 4 - 4 (subtraction property of equality)
-6 = -2x
Divide both sides by -2
-6/-2 = -2x/-2
3 = x
x = 3
Therefore, the missing value is: 3.
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hey i think TT- T but im not sure tell if im right
You labeled the triangle wrong sides 'a' and 'b' are supposed to be the sides that make the right angle. the other side is called the hypotenuse which is the longest side which you should have labeled 'c'
so Pythagorean theorem says
a^2+b^2=c^2
so
(2x+1)^2+(11x+5)^2=(12x+1)^2
distribute
(4x^2+4x+1)+(121x^2+110x+25)=(144x^2+24x+1)
add like terms
125x^2+114x+26=144x^2+24x+1
subtract 125x^2 from both sides
114x+26=19x^2+24x+1
subtract 114x from both sides
26=19x^2-90x+1
subtract 26 from both sides
0=19x^2-90-25
factor
(x-5)(19x+5)=0
therefor x-5=0 and/or 19x+5=0
so
x-5=0 add 5 to both sides
x=5
19x+5=0
subtract 5 from both sides
19x=-5
divide both sides by 19
x=-5/19
since side legnths can't be negative, we can cross this solution out
so x=5
subtitute
1+2x
1+2(5)
1+10=11
side a=11
11x+5
11(5)+5
55+5=60
side b=60
12x+1
12(5)+1
60+1=60
side c=61
add them all up
side a+b+c=11+60+61=132=total legnth
5:4
5+4=9
198/9=22
22*5=
110:88
there are 110 boys
Remember that X will always be one up or down depending on if there is a - or not (if it is just an x) and one over! Hope this helps