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3 years ago

What happens when water freezes

1 answer:

3 0

The answers would be:
A. It becomes less dense
C. It expands
If you ever noticed, ice tends to float on water.Due to Hydrogen bonding, fluid is able to be displaced when water is converted into ice which causes it to be able to float after the expansion of water. <span />

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Help!! What’s the answer

solmaris [256]

Nope the answer is condensation because because its going in, *wink* *wink*

4 0

3 years ago

it is seen that in a balloon filled with air,if we press one side of the balloon the other side bulges out.why is it so???

marshall27 [118]

When we apply pressure on the one side of balloon the other side bulges out due to the movement of gas to other side.

<h3>What happen when we press one side of the balloon?</h3>

If we press one side of the balloon, the other side bulges out because the gas that present on one side moves to the other side where there is no pressure. The body of balloon is elastic so when we apply pressure the other side bulges out.

So we can conclude that when we apply pressure on the one side of balloon the other side bulges out due to the movement of gas to other side.

Learn more about pressure here: brainly.com/question/25736513

#SPJ1

6 0

2 years ago

Froghoppers may be the insect jumping champs. These 6-mm-long bugs can spring 70 cm into the air, about the same distance as the

earnstyle [38]

Answer:

This is about 176 times the weight of the froghopper.

Explanation:

the grasshopper converts kinetic energy into earth gravitational potential energy

u=mgh

u=12*10^-3*9.8*0.7

=8.23*10^-2

using the Work energy principle

equating the kinetic energy to the potential energy

k +U+w=K2+u2

K+0+0=0+U2

k=8.23*10^-2

force exerted by the grasshopper on the round will be given by tis equation

(F-mg)Ycos $\alpha$ =k

(F-12*10^-3*9.8)*0.004cos 0=8.23*10^-2

F=20.7N

from newtons third law of motion, action and reaction are equal and opposite

F=-20.7N

comparing the forces by the two bodies

F:mg

-20.7:-12*10^-3*9.8

the magnitude of the force applied by the grasshopper is found to be 176 times the gravitational force

8 0

3 years ago

Steam enters a long, horizontal pipe with an inlet diameter of D1 = 16 cm at 2 MPa and 300°C with a velocity of 2.5 m/s. Farther

polet [3.4K]

Answer:

m = 0.4005 kg/s

Q_out = 45.1 KJ/s

Explanation:

Given

Pipe inlet diameter D1 = 16 cm

Steam inlet pressure P1 = 2 Mpa

Steam inlet temperature T1 = 300 °C

Pipe outlet diameter D2 = 14 cm

Steam inlet velocity V1 = 2.5 m/s

Steam outlet pressure P2 = 1.8 MPa

Steam outlet temperature T2 = 250 °C

Required

Determine

(a) The mass flow rate of steam.

(b) The rate of heat transfer.

Assumptions

Kinetic and potential energy changes are negligible.

This is a steady flow process.

There is no work interaction.

Solution

Part a From steam table (A-6) at P1 = 2 Mpa , T1 = 300 °C

vl = 0.12551 m^3/Kg

h1 = 3024.2 KJ/Kg

The mass flow rate of steam could be defined as the following

m = 1/v1*A1*V1

m = 0.4005 kg/s

Part b We take the pipe as our system.The energy balance could be defined as the following

E_in -E_out =ΔE_sys = 0

E_in = E_out

mh_1 = Q_out + mh_2

Q_out = m(h_1-h_2)

From steam table (A-6) at P2= 1.8 Mpa T2 = 250 °C h2= 2911.7 KJ/Kg The heat transfer could be defined as the following

Q_out = m(h_1-h_2)

Q_out = 0.4005*(3024.2 -2911.7) =45.1 KJ/s

6 0

3 years ago

Why is physics to study the heat absorbed by the ocean

Paladinen [302]

Answer:

Heat is a source of energy

Explanation:

Just took the test

5 0

3 years ago