2 years ago

Find the area of the figure

1 answer:

5 0

Find the rectangle area

A = 8*4 = 32 in²

Find the height of trapezoid

8-4 = 4 in

Find the area of trapezoid

(5,3+8)*4/2 = 13,3*4/2 = 53,2/2 = 26,6 in²

Find the figure area

26,6+32 = 58,6 in²

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Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.

Damm [24]

The answer:
<span>the two triangles are similar
in addition, the line UV is parallel to line BC, so we can use the theorem of Thales for proving the following ratios:

AV /AC = AU/ AB= UV/ BC
372/589=20x +80 / AB = 444 / 703

</span>so we get (372/589) AB - 80 = 20x, and x = ( (372/589) AB - 80 ) / 20

exact value of x depends on the value of AB

8 0

3 years ago

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$fx ^{5} d - fx ^{4 \sqrt{x + 2d} } \\$

3 0

2 years ago

The function f(x)=(x-1)^2-4 is not one-to-one. If you restrict the domain for f(x) to x(less than or equal to symbol)1, what is

olasank [31]

$\text{We have been given the function }\\
f(x)=(x-1)^2-4\\
\text{Let f(x)=y}\\
y=(x-1)^2-4\\
\text{Swap x and y, we get}\\
\\
x=(y-1)^2-4\\
\text{Now we solve for y}\\
(y-1)^2=x+4\\
\\
y-1=\pm \sqrt{x+4}\\
\\
y=1\pm \sqrt{x+4}\\
\\
f^{-1}(x)=1\pm \sqrt{x+4}\\$