I will mark brainlist please help
Story : A Dog’s Tale by Mark Twain
1. Using a dog as narrator gives the passage a tone of —
• objectivity
• formality
• bitterness
• humor
2. What literary device is used in the sentence “She had one word which she always kept on hand, and ready, like a life-preserver”?
• Simile
• Metaphor
• Hyperbole
• Onomatopoeia
3. Based on the second paragraph, the word mastiff most likely means —
• a large dog
• a male dog
• a man’s shirt
• a part of a ship
4. According to the author, what would bring such happiness to the dogs as he describes at the end of the story?
• They helped the author’s mother find the words she used, so they especially enjoyed watching her use them.
• They knew the meaning of “supererogation” and realized they were listening to a funny joke.
• Watching and laughing as others were embarrassed vindicated their own previous embarrassment.
• They were generally happy dogs who often expressed a great deal of joy.
5. “A Dog’s Tale” uses the topic of animal communication in order to —
• show how dogs really communicate
• explain how animals learn from humans
• demonstrate that dogs are smarter than most people
• poke fun at human behavior
6. The amount of time that passes during this story is most likely —
• 10 hours
• 10 days
• 10 months
• 10 years
7. An underlying theme in this story is that —
•many people use words without knowing their meanings
• dogs know more than people realize
• family loyalty takes top priority
• strangers are almost always suspicious
8. Since the author used first person, readers are left to wonder —
• how the author felt about his mother
• how strangers reacted to his mother’s word knowledge
• what the author’s mother was thinking
• whether or not the author’s mother knew the meanings of all the words she used
Answer: ![A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=A%5E%7B-1%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B2%7D%26-%5Cfrac%7B1%7D%7B2%7D%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
<u>Step-by-step explanation:</u>
![\left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%261%5C%5C4%263%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
![\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7DRow%5C%201%5Crightarrow%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26%5Cfrac%7B1%7D%7B2%7D%5C%5C4%263%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B1%7D%7B2%7D%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
![Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=Row%5C%202%20-4%20%5C%20Row%5C%201%5Crightarrow%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26%5Cfrac%7B1%7D%7B2%7D%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B1%7D%7B2%7D%260%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
![Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=Row%5C%201-%5Cdfrac%7B1%7D%7B2%7D%5C%20Row%5C%202%20%5Crightarrow%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B2%7D%26-%5Cfrac%7B1%7D%7B2%7D%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
49. 100-36= how many girls in percent
= 64%
64%= 16 girls
64/100=16/x
cross multiply
1600=64x
x=25
Answer:
(x + 1)² + (y - 1)² = 1.5625
Step-by-step explanation:
From the picture we see:
The radius is 5 units. Each unit is .25 so the radius is 1.25.
The centre or middle M= ( -1, 1 )
Circle with centre M and radius r :
(x - xM)² + (y - yM)² = r²
xM = -1
yM = 1
r = 1.25
(x - (-1))² + (y - 1)² = (1.25)²
(x + 1)² + (y - 1)² = 1.5625
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
