Let the initial count of his fish be n.
He gives away 2/3 of these fish: 2n/3, leaving n/3 fish.
He gives away 2/5 of these remaining n/3 fish: (2/5) times (n/3), or
2n
--- , meaning that (3/5) times (n/3) fish are left.
15
(3/5)(n/3) = n/5 fish left = 30 fish. Thus, n = 150 fish.
Be certain to check this answer!
Answer:
348
Step-by-step explanation:
A=2(wl+hl+hw)
2(6·9+8·9+8·6)=348
Find A cup(B cap C) . A = \{1, 4, 6, 7\}; B = \{3, 4, 5\}; C = \{2, 4, 8\}; \{1, 4, 6, 7\} 4 } \{1, 2, 3, 4, 5, 6, 7, 8\}
Inessa05 [86]
The only common element between B and C is 4, so B ∩ C = {4}.
4 is also already contained in A, so B ∩ C is a subset of A, and thus
A U (B ∩ C) = A = {1, 4, 6, 7}
Answer:
david biked 6 miles every hour!
Step-by-step explanation:
