Answer:
FV(p)= PV*(1 + g)^t
Step-by-step explanation:
Giving the following information:
Number of insects (PV)= 1,500
Increase rate= 3 weekly
<u>First, we need to calculate the daily growth rate:</u>
Daily rate (g)= [3^(1/7)] - 1
Daily rate (g)= 0.16993
<u>Now, by using the following formula, we can determine the population p in any given day t:</u>
FV(p)= PV*(1 + g)^t
<u>For, example after 7 days:</u>
FV(p)= 1,500*(1.16993^7)
FV(p)= 4,500
<u>For example, after 10 days:</u>
FV(p)= 1,500*(1.16993^10)
FV(p)= 7,206
Answer:
true
Step-by-step explanation:
Answer:
4*4=16+7=23
Step-by-step explanation:
Answer
its
www.SenatorJanSmith.gov
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Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped
