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skelet666 [1.2K]
3 years ago
5

last summer, job earned 916 mowing lawns. His brother,gabe,earned 791 completing chores in the neighborhood. compare the value o

f the 9 in each of the two numbers. how do the values compare?
Mathematics
1 answer:
enot [183]3 years ago
7 0
916...the 9 is in the hundreds place so its value is 900
791...the 9 is in the tens place so its value is 90

900/90 = 10
so the 9 in 916 is 10 times bigger then the 9 in 791
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inysia [295]

Answer:

Neighborhood Q appears to have a bigger family size

Step-by-step explanation:

Mean = the sum of all data values divided by the total number of data values

Number of families in Neighborhood Q = 9

Mean family size of Neighborhood Q:

= (2 + 5 + 4 + 3 + 2 + 5 + 3 + 6 + 5) ÷ 9

= 35 ÷ 9

= 3.888888...

Number of families in Neighborhood S = 9

Mean family size of Neighborhood S:

= (2 + 3 + 2 + 3 + 7 + 2 + 3 + 3 + 2) ÷ 9

= 27 ÷ 9

= 3

The mean family size of Neighborhood Q is 3.88..  and the mean family size of Neighborhood S is 3.  Therefore, Neighborhood Q appears to have a bigger family size as it's average family size is bigger than that of Neighborhood S.

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2 years ago
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miv72 [106K]

Answer:

c = 2 , d = 3

Step-by-step explanation:

(2y^3)(9y^3) = 18y^6

4 0
2 years ago
A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.
Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h(t)=-48t -16t^2. We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula x=-\frac{b}{2a}.

x=-\frac{-48}{2(-16)}

x=-\frac{48}{32}

x=-\frac{3}{2}

So, the x-coordinate of the parabola is -\frac{3}{2}. Now, we will substitute x=-\frac{3}{2} in our given equation to find y-coordinate of parabola.

h(t)=-48t -16t^2

h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2

h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})

h(-\frac{3}{2})=72-4*9

h(-\frac{3}{2})=72-36

h(-\frac{3}{2})=36

Therefore, the maximum height of the ball is 36 feet.

3 0
2 years ago
Solve for x in terms of a,b, and c: ax - 3b =c. . 1: a(c+3b). 2: a (c-3b). 3: c-3/a. 4: c+3b/a
trapecia [35]
We have to solve x in terms of a, b and c:
a x - 3 b = c
a x - 3 b + 3 b = c + 3 b
a x = c + 3 b
x = ( c + 3 b ) : a
Answer:
4 ) ( c + 3 b ) / a
8 0
2 years ago
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