Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
It’s going to be A. She was supposed to use distributive property
Answer:
<u> y = 19/36</u>
Step-by-step explanation:
Assuming that what you want is the value of y, you can pass all the right side stuff to the left, and the y to the right:
2/3 + 15/6 = 6y
Then you can sum the fractions on the left by using the same denominators:
4/6 + 15/6 = 6y ==> 19/6 = 6 * y
then you can pass the 6 that is multiplying on the right to the left - now dividing:
<u> y = 19/36</u>
Answer:
NUMBERS end in 12581... YEP.
Answer:
(x-y)(x+6)
Step-by-step explanation:
x^2+6x-xy-6y
x*(x+6)-y(x+6)
(x-y)(x+6)