Answer: E. Greater than 10
Step-by-step explanation:
First, know that number to the left of a number line are negative and the square of any negative number will be positive and a perfect square.
Since the square of the unknown number is less than 1/100 i.e 0.01 then the possible unknown number 'n' can be -0.01 itself, of which the square of -0.01 will give us 0.0001 (1/10,000) i.e a value less than 0.01.
The reciprocal of 1/10000 is 10,000 which is a value greater than 10.
9 - 18
5 - 10
1 - 2
Work —
First line:
y = 2 (9)
y = 18
Second line:
10 = 2x
5 = x
Third line:
y = 2 (1)
y = 2
Chu gf fr uvv V dhh gg jb cub
Answer:
Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner 
is:
where :
(a and b are the length and the breath of the rectangle respectively )
![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)
Thus; the moment of inertia of the lamina about one corner is
