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jenyasd209 [6]
2 years ago
5

When testing μ, how do we decide whether to use the standard normal distribution or a Student's t distribution? If the x distrib

ution is normal and n ≥ 30 with known σ we use the Student's t. With the same conditions and unknown σ we use the standard normal. If the x distribution is normal and n ≥ 20 with known σ we use the standard normal. With the same conditions and unknown σ we use the Student's t. If the x distribution is normal and n ≥ 30 with known σ we use the standard normal. With the same conditions and unknown σ we use the Student's t. Whenever we assume the populations are independent, we always use the standard normal.
Mathematics
1 answer:
Helga [31]2 years ago
8 0

Answer:not sure

Step-by-step explanation:

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Answer:

500 boxes

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< Since "p" stands for profits, change "p" to 0 (since the question says 0 profits).

Here is how your equation would look like:

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The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that
tekilochka [14]

Answer:

a) P(X∩Y) = 0.2

b) P_1 = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability P_1 that he must stop at the first signal but not at the second one can be calculated as:

P_1 = P(X) - P(X∩Y)

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P_2 = P(Y) - P(X∩Y)

P_2 = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

P = P_1+P_2\\P=0.16+0.31\\P=0.47

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