Answer:
Step-by-step explanation:
a) The probability that the hand contains exactly one ace
No of ways of selecting one ace and four non ace would be
=
i.e. α=778320
b) the probability that the hand is a flush
No of ways of getting a flush is either all 5 hearts or clubs of spades or dice
= 
ie. β=5148
c) the probability that the hand is a straight flush
In each of the suit to get a straight flush we must have either A,2,3,4,5 or 2,3,4,5,6, or .... or 9,10, J, q, K
So total no of ways = 
γ=46332
Answer:
Well we add together 20+15 which is 35 which is 5 over the 30 in the class so that means out of the 30 students 5 of them like both games
Hope This Helps
Answer:
The value of 
is 17-18x and 
is -7-18x.
Step-by-step explanation:
It is given in the question functions f(x) as 3x+2 and g(x)=5-6x.
It is required to find and .
To find , substitute g(x) for x in f(x) and simplify the expression.
To find , substitute f(x) for x in g(x) and simplify the expression.
Step 1 of 2
Substitute g(x) for x in f(x) and simplify the expression.
Step 2 of 2
Substitute f(x) for x in g(x) and simplify the expression.
Answer:
The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.
Step-by-step explanation:
According to DeMorgan's Theorem:
(W.X + Y.Z)'
(W.X)' . (Y.Z)'
(W'+X') . (Y' + Z')
Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.
For the original function:
(W . X + Y . Z)'
= (1 . 1 + 1 . 0)
= (1 + 0) = 1
For the compliment:
(W' + X') . (Y' + Z')
=(1' + 1') . (1' + 0')
=(0 + 0) . (0 + 1)
=0 . 1 = 0
Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.
Without the parenthesis the compliment equation looks like this:
W' + X' . Y' + Z'
1' + 1' . 1' + 0'
0 + 0 . 0 + 1
Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.
Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.
