Answer:
Step-by-step explanation:
Given that A is a square matrix and A is idempotent
Consider I-A
i) 
It follows that I-A is also idempotent
ii) Consider the matrix 2A-I
So it follows that 2A-I matrix is its own inverse.
Answer: 18x^3-9x^2+21x
Solution:
3x(6x^2-3x+7)=
Applying the distributive property in the multiplication to eliminate the parentheses:
(3x)(6x^2)+(3x)(-3x)+(3x)(7)=
(3*6)x^(1+2)+3*(-3)x^(1+1)+(3*7)x=
18x^3-9x^2+21x
Answer:
Q1. -45
Q2. -10
Q3. 31?
Step-by-step explanation:
Q1 -- you times -8 and 2 which comes out to -16. Since you have -16 + 1 inside of the parentheses you add 1 to -16 which comes out to -15. Then you take -15 times 3 and it comes out to -45.
Q2 -- the m gets replaced by the 5 so now its -2 times 5. Which comes out to -10. Then you take -10 times 2, which is -20. Now take -20 + 10 which gives us the answer of -10.
Q3 -- I'm not completely sure on this one but I think the equation would transfer to this 2*5 + 5*3 + 2*3. So 2*5 is 10, 5*3 is 15, and 2*3 is 6. Add them all together and you get 31.
I hope this was right and it helps you!
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