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Alexxx [7]
3 years ago
15

Which set of statements would describe a parallelogram that can always be classified as a rhombus?

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0
The correct answer is (4) I, II, and III.
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A graphing calculator display 1.89x10^12 as 1.89E 12. how do you think it would display 1.89x10-12? what does the E stand for.
grigory [225]

Answer:

lllllllllllllljgfygfjhfgi

6 0
3 years ago
2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,00
Luden [163]

Using the binomial distribution, it is found that:

a) There is a 0.0501 = 5.01% probability that you need to contact four people.

b) You expect to contact 1.82 students until you find one who lives within five miles of you.

c) The standard deviation is of 1.22 students.

d) 0.3369 = 33.69% probability that 3 of them live within five miles of you.

e) It is expected that 2.75 students live within five miles of you.

For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 55% live within five miles, hence p = 0.55.

Item a:

This probability is P(X = 0) when n = 3(none of the first three) multiplied by 0.55(the fourth does live within five miles), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125

p = 0.091125(0.55) = 0.0501

0.0501 = 5.01% probability that you need to contact four people.

Item b:

The expected number of trials in the binomial distribution until q successes is given by:

E = \frac{q}{p}

In this problem, p = 0.55, and 1 trial, thus q = 1, hence:

E = \frac{1}{0.55} = 1.82

You expect to contact 1.82 students until you find one who lives within five miles of you.

Item c:

The standard deviation of the number of trials until q successes are found is given by:

S = \frac{\sqrt{q(1 - p)}}{p}

Hence:

S = \frac{\sqrt{0.45}}{0.55} = 1.22

The standard deviation is of 1.22 students.

Item d:

This probability is <u>P(X = 3) when n = 5</u>, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.55)^{3}.(0.45)^{2} = 0.3369

0.3369 = 33.69% probability that 3 of them live within five miles of you.

Item e:

The expected value of the binomial distribution is:

E(X) = np

Hence:

E(X) = 5(0.55) = 2,75

It is expected that 2.75 students live within five miles of you.

A similar problem is given at brainly.com/question/25343741

6 0
3 years ago
What’s the solution to 2x - 2 &gt; 2x + 4 ?
kotegsom [21]

Answer:

This inequality isn't correct.

Step-by-step explanation:

2x - 2 > 2x + 4

Substituting any value for x, the result will be incorrect.

Actually,

2x - 2 < 2x + 4 is correct.

2x - 2x < 4 + 2

0 < 6

6 0
3 years ago
Which ordered pair comes from the table
Reil [10]

Answer:

B: (6, 5)

Step-by-step explanation:

If you compare the table with the answers, answer B is the only answer that has a matching pair on the table.

Thanks for posting your question! If correct, please award brainliest!

7 0
3 years ago
Read 2 more answers
guys pls i post two more questions that i dont kno and i want to pass my test sorry ,but they are important
Andrej [43]
Okkk .. this is what this app is for anyways to help.
5 0
3 years ago
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