Solve the equation by finding the extraneous solutions:
|x-2| = 3x-4
1 answer:
If you have
|a|=b
assume
a=b and -a=b
|x-2|=3x-4
assume
x-2=-3x-4
-(x-2)=3x-4
solve each
x-2=3x-4
minus x from both sides
-2=2x-4
add 4 to both sides
2=2x
divide both sides by 2
1=x
-(x-2)=3x-4
-x+2=3x-4
add x to both sides
2=4x-4
add 4 to both sides
6=4x
divide both sides by 4
1.5=x
x=1 or 1.5
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