I believe your answer is D!
Sequence: 3/4, 3/16, 3/64, 3/256
a8=?
a1=3/4
a2=3/16
a3=3/64
a4=3/256
a2/a1=(3/16)/(3/4)=(3/16)*(4/3)=4/16=1/4
a3/a2=(3/64)/(3/16)=(3/64)*(16/3)=16/64=1/4
a4/a3=(3/256)/(3/64)=(3/256)*(64/3)=64/256=1/4
a2/a1=a3/a2=a4/a3=r=1/4
an=a1*r^(n-1)
an=(3/4)*(1/4)^(n-1)
an=(3/4)*(1)^(n-1)/(4)^(n-1)
an=(3/4)*(1/4^(n-1))
an=(3*1)/[4*4^(n-1)]
an=3/4^(1+n-1)
an=3/4^n
n=8→a8=3/4^8
a8=3/65,536
Answers:
The general term or nth term for the sequence is: an=3/4^n
a8=3/65,536
Answer:
She will have 7 dollars, with 96 cents remaining.
Step-by-step explanation:
326 pennies is $3.26
64 nickels is $3.20
15 dimes is $1.50
Add them all;
$3.26 + $3.20 + $1.50 = $7.96
She will have 7 dollars, with 96 cents remaining
Answer:
FV= $34,222.33
Step-by-step explanation:
<u>First, we need to calculate the weekly interest rate:</u>
Weekly interest rate= 0.0289/52= 0.00056
<u>To calculate the future value (FV), we need to use the following formula:</u>
FV= {A*[(1+i)^n-1]}/i
A= weekly deposit
n= 15*52= 780
A= $35
FV= {35*[(1.00056^780) - 1]} / 0.00056
FV= $34,222.33
Answer:
The confidence interval for the proportion of production lines that caused defects is (0.07, 0.09).
Step-by-step explanation:
A confidence interval for a population proportion is a function of the sample proportion and the margin of error.
The interval has two bounds, a lower bound and an upper bound.
The lower bound is the sample proportion subtracted by the margin of error.
The upper bound is the margin of error added to the sample proportion.
In this problem, we have that:
Sample proportion 0.08
Margin of error 0.01
0.08 - 0.01 = 0.07
0.08 + 0.01 = 0.09
The confidence interval for the proportion of production lines that caused defects is (0.07, 0.09).
