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Roman55 [17]
3 years ago
7

Which rule describes the translation EFG → E′F′G′?

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0

Answer:

The answer is (x, y) → (x + 6, y + 1)

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17. A baseball trading card is sold for $2, and its
Sidana [21]

Answer:

$4.32

Step-by-step explanation:

8% can be represented as 1.08

2 x 1.08 = 2.16

2 x 1.08 x 1.08 = 2.33

2 x 1.08 x 1.08 x 1.08 = 2.52

etc. all the way up to 10

6 0
3 years ago
Read 2 more answers
Write a transformation rule for a function that is shifted 4 units to the right
Annette [7]

Take for example the function y = 2x + 3

In order to shift this function 4 units to the right, we must subtract from the first term.

The new function would be y = (2x - 4) + 3

3 0
3 years ago
A college reported that 40% of its population is male. Nine students are selected at random
photoshop1234 [79]

Answer:

<h2>The probability of being all females is 60%.</h2><h2>The probability of being all males is 40%.</h2>

Step-by-step explanation:

We know that 40% of the population is male.

If someone selected 9 students, the probability of being all males is 40%. But, the probability of being all females is 60%, because there are only two genders and females represents the complete set of the given probability.

8 0
4 years ago
A rectangular room has a perimeter of 70 m and is 20m long. write and equation to represent the area
Andrew [12]

Answer:

Square Footage = 15,069.47 ft²

Square Yards = 1,674.39 yd²

Square Meters = 1,400 m²

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3 0
4 years ago
. A random sample of 100 children with working mothers showed that they were absent from school an average of 6 days per term wi
erica [24]

Answer:

a) The equation is:

Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples

b) The 98% confidence interval = (5.62784, 6.37216)

Step-by-step explanation:

a. Write down the equation you should use to construct the confidence interval for the average number of days absent per term for all the children. (10 points)

Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples

b. Determine a 98% confidence interval estimate for the average number of days absent per term for all the children. (10 points)

Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples

Mean = 6 days

Standard deviation = 1.6 days

Number of samples = 100

Z score of 98% confidence interval = 2.326

Confidence interval = 6 ± 2.326 × 1.6/√100

= 6 ± 2.326 × 1.6/10

= 6 ± 0.37216

= 6 - 0.37216

= 5.62784

6 + 0.37216

= 6.37216

Therefore, the 98% confidence interval = (5.62784, 6.37216)

6 0
3 years ago
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