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Luba_88 [7]
4 years ago
10

What is the value of the expression?

Mathematics
1 answer:
bulgar [2K]4 years ago
5 0
The answer is 64. You must follow the order of operations, so you do what is in the parenthesis first. 15-7=8 and 5+3=8. Once you calculate that, you do 8×8=64.
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Vickie made a recipe for 144 fluid ounces of scented candle wax. How many 1-cup candle molds can she fill with the recipe
Gre4nikov [31]

there are 0.125 cups inside 1 fluid ounces

144 / 0.125 = 1152 (divide because you are trying to figure out how many of the volumes of the mold can fit inside the 144 fluid ounces

You can fill 1152 molds with 144 fluid ounces

3 0
4 years ago
a. it is a multiple of 3,b. is greater then 100 ,c. it is not even, d.all digits are odd. whats the number?
uranmaximum [27]

Answer:

333.

Step-by-step explanation:

3•111=333

333>100

All the digits are odd...


4 0
3 years ago
Each item produced by a certain manufacturer is independently of acceptable quality with probability 0.95. Approximate the proba
Diano4ka-milaya [45]

Answer:

The probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

Step-by-step explanation:

Let <em>X</em> = number of items with unacceptable quality.

The probability of an item being unacceptable is, P (X) = <em>p</em> = 0.05.

The sample of items selected is of size, <em>n</em> = 150.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and <em>p</em> = 0.05.

According to the Central limit theorem, if a sample of large size (<em>n</em> > 30) is selected from an unknown population then the sampling distribution of sample mean can be approximated by the Normal distribution.

The mean of this sampling distribution is: \mu_{\hat p}= p=0.05

The standard deviation of this sampling distribution is: \sigma_{\hat p}=\sqrt{\frac{ p(1-p)}{n}}=\sqrt{\frac{0.05(1-.0.05)}{150} }=0.0178

If 10 of the 150 items produced are unacceptable then the probability of this event is:

\hat p=\frac{10}{150}=0.067

Compute the value of P(\hat p\leq 0.067) as follows:

P(\hat p\leq 0.067)=P(\frac{\hat p-\mu_{p}}{\sigma_{p}} \leq\frac{0.067-0.05}{0.0178})=P(Z\leq 0.96)=0.8315

*Use a <em>z</em>-table for the probability.

Thus, the probability that at most 10 of the next 150 items produced are unacceptable is 0.8315.

5 0
3 years ago
How much money will the movie theater make if a birthday party of 12 kids each buys a box of candy and a soda but does not go se
Hunter-Best [27]

Answer:

$93

Step-by-step explanation:

12(3.75+4.00)

= 93

4 0
3 years ago
Please help me with all thank you in advance
balu736 [363]

Answer:

1232i34iu494232759375r

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
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