Answer:
f(1) ≈ 2.7864
Step-by-step explanation:
You appear to want a couple of iterations of ...
... y[n+1] = y[n] +arcsin(x[n]·y[n]}·(x[n+1] -x[n])
... x[n+1] = x[n] +0.5
... x[0] = 0
... y[0] = 2
Filling in the values, we get
... y[1] = 2 + arcsin(0·2)·0.5 = 2
... y[2] = 2 + arcsin(0.5·2)·0.5 = 2 +(π/2)·0.5 ≈ 2.7864 . . . . corresponds to x=1
Answer:
29-(2c+3)=2(c+3)+c=
We move all terms to the left:
29-(2c+3)-(2(c+3)+c)=0
We get rid of parentheses
-2c-(2(c+3)+c)-3+29=0
Step-by-step explanation:
There are 45 oranges and 90 apples in the beginning.
Step-by-step explanation:
Let the no. of orange be 'b'
Let the no. of apples be 'a'
Given that,
2b = a
3(b-15) = a
3b - 45 = a
3b - 45 = 2b
3b - 2b = 45
b = 45
2b = a
2(45) = a
a = 90
There are 45 oranges and 90 apples in the beginning.
Answer:
745
Step-by-step explanation:
Divide 31 by 2 and you will get 15.5
