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3 years ago

12

Solve the system of equations

2 answers:

Viefleur [7K]3 years ago

7 0

Answer:

Step-by-step explanation:

prisoha [69]3 years ago

4 0

Answer:

x=−6,y=24

x=2,y=−8

Step-by-step explanation:

Graph if needed:

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1000miles per hour

Step-by-step explanation:

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3 years ago

Help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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(4/2)4 + (1 + 3)?<br><br> I really need help!

Katyanochek1 [597]

$\huge\text{Hey there!}$

$\large\text{Just do PEMDAS}$

$\large\text{Parentheses}$

$\large\text{Exponents}$

$\large\text{Multiplication}$

$\large\text{Division}$

$\large\text{Addition}$

$\large\text{Subtraction}$

$\mathsf{(\dfrac{4}{2})(4) + (1+3)}$

$\mathsf{\dfrac{4}{2} = 2}$

$\mathsf{2(4) + (1 + 3)}$

$\mathsf{2(4) = 8}$

$\mathsf{8 + (1 + 3)}$

$\mathsf{1 + 3 = 4}$

$\mathsf{8 + 4 = 12}$

$\boxed{\boxed{\large\text{Answer: \bf \huge12 }}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day! }$

~ $\frak{Amphitrite1040:)}$

6 0

3 years ago

Consider rolling a fair die twice and tossing a fair coin eleven times. Assume that all the tosses and rolls are independent. Th

marin [14]

Answer:

0.005371

Step-by-step explanation:

Given that a fair coin is tossed 11 times.

Since coin is fair probability for head p = 0.5 and q = prob for tail =0.5

Each trial is independent of the other. Hence X no of heads is binomial with $n = 11 and p =0.5$

Prob for getting 10 heads out of 11 tosses

=P(X=10)

= $11C10 (0.5)^{10} (0.5)\\= 0.005371$

3 0

3 years ago

309 ,009 ,990 in expanded form

Mrac [35]

300 + 0 +9,

0 + 0 + 9

900 + 90

8 0

3 years ago