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WARRIOR [948]
3 years ago
13

The area of a room is 396 square feet. The length is x+3, and the width is x+7 feet. Find the dimensions of the room

Mathematics
1 answer:
Marrrta [24]3 years ago
3 0
This is an odd problem. The length and width look like they should be interchanged. Anyway I'll solve it and we'll talk about the results.
(x +7) (x + 3) = 396
x^2 + 7x + 3x + 21 = 396
x^2 + 10x + 21 = 396 Subtract 21 from both sides.
x^2 + 10x = 396 - 21
x^2 + 10x = 375
x^2 + 10x - 375 = 0 This probably factors.
(x + 25)(x - 15)
x + 25 = 0
x = - 25 which makes no sense. Negatives do not describe room dimensions.
x - 15= 0
x = 15. this is fine.

x+3 = 15 + 3 = 18
x + 7 = 15 + 7= 22

Check
=====
Area = L * W = 18 * 22 = 496. It does check.
22 should be the length

18 should be the width.
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lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>  

2 = (2/3) 0 + b   => b = 2

Therefore    y = (2/3)x + 2

The bottom line appears to pass through the points (0,-1) and (3,1)

For this line

m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,-1) set x = 0, y= -1  in y = (2/3)x + b =>  

-1  = (2/3) 0 + b   => b = -1

Therefore    y = (2/3)x + -1

Thank you,

MrB

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3 years ago
62+x=82<br><br><br> Does any one know this answer
Vladimir [108]

62 + x = 82

Subtract both sides by 62.

x = 20.

4 0
3 years ago
Read 2 more answers
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