Answer:
The number ins't simplified
Step-by-step explanation:
If you convert it into a mixed number it will be a lot easier to see where it goes. In this case tho 6 divided by 3 just equals 2, so the two is what you put on a number line.
Answer:
The the angle which the wire make with the ground is 1.280 radian .
Step-by-step explanation:
Given as :
The length of the wire attached to the top of building = OB = 70 foot
The distance of wire anchored from base of ground = OA = 20 feet
Let the angle made by wire en and ground = Ф
Now from , In Triangle AOB
Cos angle = 
Or, Cos Ф = 
or, Cos Ф = 
Or, Cos Ф = 
∴ Ф = 
I.e Ф = 73.39°
Now in radian ,
∵ 180° = 
radian
∴ 73.39° = 
× 73.39°
= 
× 73.39° = 1.280 radian
Hence The the angle which the wire make with the ground is 1.280 radian . Answer
125 ÷ 3 = 41.6666666667
41.66666666667 X 2
= 83.3333......
Technically not correct, because you cannot split sixth graders into pieces, so you would probably round it to 84 students.
Answer:
The answer is 8.6×10¹⁴
Step-by-step explanation:
You can evaluate it :
Answer:
n squared + 3n + 1
Step-by-step explanation:
5,11,19,29
Firstly look at the difference between each number. The first difference is 6 then 8 then 10 etc. After that you look at your created sequence - 6,8,10 etc. The difference is 2 each time. Then applying rules, you have to do the constant difference divided by 2 to get a coefficient of n squared. So in this case it's n squared because 2/2 = 1 so you don't have to place a 1 in front of the n squared. After you create a sequence from the n squared. That would be 1,4,9 etc. Then you need to see how to get from the sequence: 1,4,9 etc to your original sequence: 5,11,19 etc. So if you calculate it you will get 4,7,10 because firstly 5-1 = 4 then 11-4 = 7 etc. The sequence 4,7,10 is a linear sequence so the constant difference is 3 each time. So to get a nth term of a linear sequence you will start off as 3n then you will substitute 1 then 2 then 3 into the 3n. Therefore that would be 3,6 etc. So if you take the first substituted term, that would be 3 as said before then you will have to see how to get from the 3 to 4 so that is just adding 1. So the nth term of this linear sequence is 3n + 1. Check if it works at the end. So the overall nth term of the quadratic sequence is n squared as said before + 3n + 1.
