Ask question

Ask question

All categories

3 years ago

12

Write this number in standard form 12 ten thousands, 8 thousands, 14 hundreds, 7 ones

2 answers:

Maurinko [17]3 years ago

6 0

I believe it would be 128,147

Hope this helps :)

crimeas [40]3 years ago

4 0

128,147.
Hope this helps :)

You might be interested in

What is the product of 3x1/5?

vagabundo [1.1K]

Answer: 3/5

Step-by-step explanation: 1/5*3=1/5+1/5+1/5=3/5

7 0

3 years ago

How can the community property be used to write multiplication sentences?

Julli [10]

<span> allows you to </span>do<span> repeated addition quickly and efficiently</span>

5 0

3 years ago

2) Which ordered pairs represent a proportional relationship between x and y?

ZanzabumX [31]

Answer:

d

Step-by-step explanation:

you can multiply the original x and y by 3 and get the second x and y

i hope this helps

4 0

3 years ago

Read 2 more answers

Line p passes through A(-2, -4) and has a slope of - 1/2

Alenkasestr [34]

M = -1/2
(x₁, y₁) = (-2,-4)

Find the equation
y - y₁ = m(x - x₁)
y - (-4) = -1/2 (x - (-2))
y + 4 = -1/2 (x + 2)
2(y + 4) = -1 (x + 2)
2y + 8 = -x - 2
x + 2y = -10

8 0

3 years ago

denis-greek [22]

Answer:

$\frac{3\±\sqrt{3}}{3}$

Step-by-step explanation:

Whe have the function $3x^2-6x+2=0$

To solve this equation we must factor.

To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula

$\frac{-b\±\sqrt{b^2-4ac}}{2a}$

Where:

a = 3

b = -6

c = 2

Then

$\frac{-(-6) + \sqrt{(-6)^2-4(3)(2)}}{2(3)} = \frac{3+\sqrt{3}}{3}\\\\and\\\\\frac{-(-6) - \sqrt{(-6)^2-4(3)(2)}}{2(3)}= \frac{3-\sqrt{3}}{3}$

finally the correct answer is $\frac{3\±\sqrt{3}}{3}$

5 0

3 years ago

Read 2 more answers