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4 years ago

Solve 3y^{2} - (y + 2) (y - 2)

Mathematics

2 answers:

hram777 [196]4 years ago

8 0

Answer:

3y^2 - (y + 2) (y - 2) = 0

<=> 3y^2 - (y^2 - 4) = 0

<=> 2y^2 + 4 =0

<=>y^2 + 2 = 0

=> Because y^2 is always equal or larger than 0, there is no real solution.

Hope this helps!

Paladinen [302]4 years ago

8 0

Answer:

$2 {y}^{2} + 4$

Step-by-step explanation:

$3 {y}^{2} - (y + 2)(y - 2) \\ 3 {y}^{2} - ( {y}^{2} - 4) \\ 3 {y}^{2} - {y}^{2} + 4 \\ = 2 {y}^{2} + 4 \\ = 2( {y}^{2} + 2)$

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