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3 years ago

Solve 3y^{2} - (y + 2) (y - 2)

Mathematics

2 answers:

hram777 [196]3 years ago

8 0

Answer:

3y^2 - (y + 2) (y - 2) = 0

<=> 3y^2 - (y^2 - 4) = 0

<=> 2y^2 + 4 =0

<=>y^2 + 2 = 0

=> Because y^2 is always equal or larger than 0, there is no real solution.

Hope this helps!

Paladinen [302]3 years ago

8 0

Answer:

$2 {y}^{2} + 4$

Step-by-step explanation:

$3 {y}^{2} - (y + 2)(y - 2) \\ 3 {y}^{2} - ( {y}^{2} - 4) \\ 3 {y}^{2} - {y}^{2} + 4 \\ = 2 {y}^{2} + 4 \\ = 2( {y}^{2} + 2)$

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Write an expression for the area of the shaded region in its simplest form. Show all of your steps.

netineya [11]

The area of the shaded region is going to be the area of the rectangle minus the area of the square.

Area of a rectangle is L * W.
A = L * W
A = (x + 10)(2x + 5)
A = x(2x + 5) + 10(2x + 5)
A = 2x^2 + 5x + 20x + 50
A = 2x^2 + 25x + 50 .....this is the area of the rectangle

area of a square is : A = a^2...where a is one side
A = (x + 1)^2
A = (x + 1)(x + 1)
A = x(x + 1) + 1(x + 1)
A = x^2 + x + x + 1
A = x^2 + 2x + 1

now we subtract the area of the square from the area of the rectangle to get the area of the shaded region.

2x^2 + 25x + 50 - (x^2 + 2x + 1) =
2x^2 + 25x + 50 - x^2 - 2x - 1 =
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2 years ago

7a +42 +8< -10 + 9a -64a

Mamont248 [21]

Answer:

a < -30/31

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

7a + 42 + 8 < -10 + 9a - 64a

Step 2: Solve for a

Combine like terms (a): 7a + 42 + 8 < -10 - 55a
Combine like terms: 7a + 50 < -10 - 55a
[Addition Property of Equality] Add 55a on both sides: 62a + 50 < -10
[Subtraction Property of Equality] Subtract 50 on both sides: 62a < -60
[Division Property of Equality] Divide 62 on both sides: a < -30/31

Here we see any number a less than -30/31 would work as a solution to the inequality.

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AveGali [126]

Answer:

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Step-by-step explanation:

the formula of the area of the circle is πr^2

if the radius is 6, then its 6*6*π which is 36π

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