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oksano4ka [1.4K]
3 years ago
12

Solve 3y^{2} - (y + 2) (y - 2)

Mathematics
2 answers:
hram777 [196]3 years ago
8 0

Answer:

3y^2 - (y + 2) (y - 2) = 0

<=> 3y^2 - (y^2 - 4) = 0

<=> 2y^2 + 4 =0

<=>y^2 + 2 = 0

=> Because y^2 is always equal or larger than 0, there is no real solution.

Hope this helps!

:)

Paladinen [302]3 years ago
8 0

Answer:

2 {y}^{2}  + 4

Step-by-step explanation:

3 {y}^{2}  - (y + 2)(y - 2) \\ 3 {y}^{2}  - ( {y}^{2}  - 4) \\ 3 {y}^{2}  -  {y}^{2}  + 4 \\  = 2 {y}^{2}  + 4 \\  = 2( {y}^{2}  + 2)

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