Y +3= = (x - 1) What point does the line go through? a (3 11

Mathematics

1 answer:

kolbaska11 [484]3 years ago

5 0

Answer:

y=-- 4/3 x + 7/3

Step-by-step explanation:

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9x-23=49 what is the second step in this equation?

ladessa [460]

Answer:

Divide both sides by 9.

Step-by-step explanation:

To find the second step of the equation, we actually have to solve parts of the equation until we get to step 2.

Step 1: Add 23 to both sides.

$9x - 23 + 23 = 49 + 23$
$9x = 72$

Step 2: Divide both sides by 9.

$\frac{9x}{9} = \frac{72}{9}$
$x = 8$

Therefore, the second step is divide both sides by 9.

Have a lovely rest of your day/night, and good luck with your assignments! ♡

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2 years ago

Prepare a probability distribution for the experiment. Let x represent the random variable, and let P represprobability22) Two b

iVinArrow [24]

The total ball in the bag is 4 + 2 = 6 balls. Their are 4 red balls and 2 blue balls.

If they are drawn singly the probability that 2 blue balls are counted can be expressed as follows

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3 0

10 months ago

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$