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3 years ago

HELP ASAP PLEASE!

Mathematics

2 answers:

andreev551 [17]3 years ago

5 0

Answer:

start with 4, and multiply by 2 repeatedly

Step-by-step explanation:

wlad13 [49]3 years ago

3 0

Start with 4 and multiply by 2 repeatedly

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Nick works as a waiter. He earns $75 each weekend plus 15% in tips on meals served. Nick served $675 worth of meals last weekend

maxonik [38]

Answer:

$Nick's\ earning=\$ 176.25$

Step-by-step explanation:

Let total meal served $=\$x$

$Tip=15\%\ of x=\frac{15}{100}x=0.15x\\\\Nick's\ earning=75+0.15x\\\\Here\ x=\$675\\\\Nick's\ earning=75+0.15\times 675=75+101.25=\$ 176.25$

7 0

4 years ago

Which table has greater constant of proportionality?

marissa [1.9K]

The table with greater proportionality is table 3.

<h3>What is constant proportionality?</h3>

The constant of proportionality is the ratio between two directly proportional quantities.

As, the constant proportionality is

k= y/x

For table 1,

k = 1/1 = 2/2 =1

For table 2,

k = 6/1= 12/2 = 2

For table 3,

k = 5/1 = 10/2 = 5

For table 4,

k = 4/1 = 8/2 = 4

Hence, table 3 is with greater proportionality.

Learn more about this constant of proportionality here:

brainly.com/question/8598338

#SPJ1

8 0

2 years ago

Find a particular solution to y" - y + y = 2 sin(3x)

leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

$\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x$

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

$=e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}$

Multiplying both sides of equation (1) by integrating factor and integrating we get

$\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I$

$I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx$