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3 years ago

15

What's 75/100 in simplest form

1 answer:

bagirrra123 [75]3 years ago

7 0

Divide the numerator and denominator by their gcf (25)
75/25= 3
100/25= 4

Final answer: 3/4

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An exponential function f(x) is reflected across the y-axis to create function g(x). Which is a true statement regarding f(x) an

Kobotan [32]

It's B, I'm doing my online school assignment and this was the correct answer.

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3 years ago

Read 2 more answers

Please help me please I only have a couple hours left and this is taking soooo much time

Makovka662 [10]

Answer:

it would be the first answer

Step-by-step explanation:

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3 years ago

Determine whether the triangles are similar by aa , ss , or sas ??

max2010maxim [7]

Answer:

1. AA

2. SSS

3. I´m not sure about this one, I´m sorry

4. Not similar

Step-by-step explanation:

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4 0

3 years ago

...................................................

snow_lady [41]

Answer:

3x + 2 = 59

Step-by-step explanation:

because the total is 59 so is definetly =59

and no of oranges in bag so there are 3 bags it means its 3x so the equation is 3x + 2 = 59

Hope it will help you

Lots of love from nepal <3 :)

5 0

2 years ago

Find the solution of the given initial value problem in explicit form. y′=(1−5x)y2, y(0)=−12 Enclose numerators and denominators

Nata [24]

Answer:

The solution is $y=-\frac{12}{12x-30x^2+1}$ .

Step-by-step explanation:

A first order differential equation $y'=f(x,y)$ is called a separable equation if the function $f(x,y)$ can be factored into the product of two functions of $x$ and $y$ :

$f(x,y)=p(x)h(y)$

where $p(x)$ and $h(y)$ are continuous functions.

We have the following differential equation

$y'=(1-5x)y^2, \quad y(0)=-12$

In the given case $p(x)=1-5x$ and $h(y)=y^2$ .

We divide the equation by $h(y)$ and move $dx$ to the right side:

$\frac{1}{y^2}dy\:=(1-5x)dx$

Next, integrate both sides:

$\int \frac{1}{y^2}dy\:=\int(1-5x)dx\\\\-\frac{1}{y}=x-\frac{5x^2}{2}+C$

Now, we solve for $y$

$-\frac{1}{y}=x-\frac{5x^2}{2}+C\\-\frac{1}{y}\cdot \:2y=x\cdot \:2y-\frac{5x^2}{2}\cdot \:2y+C\cdot \:2y\\-2=2yx-5yx^2+2Cy\\y\left(2x-5x^2+2C\right)=-2\\\\y=-\frac{2}{2x-5x^2+2C}$

We use the initial condition $y(0)=-12$ to find the value of C.

$-12=-\frac{2}{2\left(0\right)-5\left(0\right)^2+2C}\\-12=-\frac{1}{c}\\c=\frac{1}{12}$

Therefore,

$y=-\frac{2}{2x-5x^2+2(\frac{1}{12})}\\y=-\frac{12}{12x-30x^2+1}$

4 0

2 years ago