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ki77a [65]
4 years ago
15

What's 75/100 in simplest form

Mathematics
1 answer:
bagirrra123 [75]4 years ago
7 0
Divide the numerator and denominator by their gcf (25)
75/25= 3
100/25= 4

Final answer: 3/4
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Give the potion of C on this line
9966 [12]

Answer:


Step-by-step explanation:

its 0 to 1 so you count the lines in the middle of the 0 and 1 and there's 7 so if 8/8 is one than point C is on 3/8

4 0
4 years ago
The three circles are all centered at the center of the board and are of radii 1, 2, and 3, respectively.Darts landing within th
FromTheMoon [43]

Answer:

a) P=0.262

b) P=0.349

c) P=0.215

d) E(x)=12.217

e) P=0.603

Step-by-step explanation:

The question is incomplete.

Complete question: "The three circles are all centered at the center of the board (square of side 6) and are of radii 1, 2, and 3, respectively.Darts landing within the circle of radius 1 score 30 points, those landing outside this circle, butwithin the circle of radius 2, are worth 20 points, and those landing outside the circle of radius2, but within the circle of radius 3, are worth 10 points. Darts that do not land within the circleof radius 3 do not score any points. Assume that each dart that you throw will land on a point uniformly distributed in the square, find the probabilities of the accompanying events"

(a) You score 20 on a throw of the dart.

(b) You score at least 20 on a throw of a dart.

(c) You score 0 on a throw of a dart.

(d) The expected value on a throw of a dart.

(e) Both of your first two throws score at least 10.

(f) Your total score after two throws is 30.

As the probabilities are uniformly distributed within the area of the board, the probabilities are proportional to the area occupied by the segment.

(a) To score 20 in one throw, the probabilities are

P(x=20)=P(x=20\&30)-P(x=30)=\frac{\pi r_2^2}{L^2} -\frac{\pi r_1^2}{L^2}\\\\P(x=20)=\frac{\pi(r_2^2-r_1^2)}{L^2}=\frac{3.14*(2^2-1^2)}{6^2}=\frac{3.14*3}{36} =0.262

(b) To score at least 20 in one throw, the probabilities are:

P(x\geq 20)=P(x=20\&30)=\frac{\pi r_2^2}{L^2}=\frac{3.14*2^2}{6^2} =0.349

(c) To score 0 in one throw, the probabilities are:

P(x=0)=1-P(x>0)=1-\frac{\pi r_3^2}{L^2} =1-\frac{3.14*3^2}{6^2} =1-0.785=0.215

(d) Expected value

E(x)=P(0)*0+P(10)*10+P(20)*20+P(30)*30\\\\E(x)=0+\frac{\pi(r_3^2-r_2^2)}{L^2}*10+ \frac{\pi(r_2^2-r_1^2)}{L^2}*20+\frac{\pi(r_1^2)}{L^2}*30\\\\E(x)=\pi[\frac{(3^2-2^2)}{6^2}*10+\frac{(2^2-1^2)}{6^2}*20+\frac{1^2}{6^2}*30]\\\\E(x)=\pi[1.389+1.667+0.833]=3.889\pi=12.217

(e) Both of the first throws score at least 10:

P(x_1\geq 10; x_2\geq 10)=P(x\geq 10)^2=(\frac{\pi r_3^2}{L^2} )^2=(\frac{3.14*3^2}{6^2} )^2=0.785^2=0.616

(f) Your total score after two throws is 30.

This can happen as:

1- 1st score: 30, 2nd score: 0.

2- 1st score: 0, 2nd score: 30.

3- 1st score: 10, 2nd score: 20.

4- 1st score: 20, 2nd score: 10.

1 and 2 have the same probability, as do 3 and 4, so we can add them.

P(2x=30)=2*P(x_1=30;x_2=0)+2*P(x_1=20;x_2=10)\\\\P(2x=30)=2*P(x_1=30)P(x_2=0)+2*P(x_1=20)P(x_2=10)\\\\P(2x=30)=2*\frac{\pi r_1^2}{L^2}*(1-\frac{\pi r_3^2}{L^2})+2*\frac{\pi(r_2^2-r_1^2)}{L^2}*\frac{\pi(r_3^2-r_2^2)}{L^2}\\\\P(2x=30)=2*\frac{\pi*1^2}{6^2}*(1-\frac{\pi*3^2}{6^2})+2*\frac{\pi(2^2-1^2)}{6^2}*\frac{\pi(3^2-2^2)}{6^2}\\\\P(2x=30)=2*0.872*0.215+2*0.262*0.436=0.375+0.228=0.603

6 0
3 years ago
The world record for the greatest temperature range recorded in one day occurred in Browning, Montana, in 1916.
Vanyuwa [196]

Answer:

I need points lol

Step-by-step explanation:

gehegrhehhehfhhrhejrjr

3 0
3 years ago
I
Dafna11 [192]

Answer:

$154,763.5

Step-by-step explanation:

A = P(1 + r/n)^nt

Where,

A = future value

P = present value

r = interest rate

n = number of periods

t = time (years)

P = 97,000

r = 6% = 0.06

n = 365

t = 8 years

A = P(1 + r/n)^nt

= 97,000(1 + 0.06/365)^365*8

= 97,000(1 + 0.00016)^2,920

= 97,000(1.00016)^2,920

= 97,000(1.5955)

= 154,763.5

A = $154,763.5

4 0
3 years ago
Read 2 more answers
PLEASE HELP WITH B OR C ASAP ❤️
Monica [59]

a)

Each angle of the equilateral triangle is 180/3 = 60 degrees. Each angle of the square is 90 degrees. Focus on the angles around the top vertex of the equilateral triangle. We have 2 angles from the square and one angle from the equilateral triangle, so 2*90+60 = 180+60 = 240 degrees is accounted for so far, leaving 360-240 = 120 degrees left over for the northernmost triangle.

The northernmost triangle is isosceles because the squares all have the same side lengths (due to the fact they match up with an equilateral triangle where all the sides are the same here as well). Isosceles triangles have congruent base angles, in this case both are x degrees. Add up the angles of this northernmost triangle and set this equal to 180. Solve for x.

x+120+x = 180

2x+120 = 180

2x = 180-120

2x = 60

x = 60/2

x = 30

=====================================================

b)

The angle x combines with the 90 degree adjacent angle of the square to get 90+x = 90+30 = 120. Each interior angle of this odd hexagon is 120 degrees. Focus on the entire figure overall.

====================================================

c)

The interior angles of any pentagon always add to 180(n-2) = 180(5-2) = 540 degrees. Assuming this is a regular pentagon, each interior angle of the regular pentagon is 540/5 = 108 degrees.

Focus on the northern most point on the pentagon. The angles attached to this point are the two square angles of 90 degrees each and the 108 degrees from the interior angle of a pentagon. We have 2*90+108 = 288 degrees so far, and 360-288 = 72 degrees left over for the bottom angle of the northern most triangle.

Again we have an isosceles triangle, so the base angles are both x

x+x+72 = 180

2x+72 = 180

2x = 180-72

2x = 108

x = 108/2

x = 54

And,

90+x = 90+54 = 144 represents each interior angle of this strange looking decagon.

4 0
3 years ago
Read 2 more answers
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