Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Formula: sqr((x2-x1)^2 + (y2-y1)^2)
sqr((-4-2)^2 + (-7+2)^2)
sqr(-6)^2 + (-5)^2)
sqr(36)+(25)) = sqr(61)
The answer is A. sqr(61)
Answer:
y= -10x +12
Step-by-step explanation:
To get the result we can use knowledge that reading is 2 times longer than HW.
To find this value we just have to multiply 42 times 2 so
40*2=80
Its 1 hour and 20 min - its the result
Answer: option c
Step-by-step explanation:
To solve this problem you must keep on mind the properties of logarithms:
Therefore, knowing the properties, you can write the expression gven in the problem as shown below:
