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Harlamova29_29 [7]
3 years ago
12

How to do distributive property with an unknown variable.

Mathematics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

1. Multiply, or distribute, the outer term to the inner terms.

2. Combine like terms.

3. Arrange terms so constants and variables are on opposite sides of the equals sign.

4. Solve the equation and simplify, if needed

Step-by-step explanation:

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5 0
3 years ago
Please someone do this for me
ss7ja [257]

Answer:

A = -12

Step-by-step explanation:

A   put in -2 for 'x' in the equation to find value

       2(-2)  - y = 8       add 4 to both sides

              -y = 12

               y = -12              

        I think YOU can now find B and C  with this method !

3 0
2 years ago
Read 2 more answers
Which of the following is true regarding the transition elements? A. Multiple oxidation states resulting from the involvement of
blsea [12.9K]

Answer:

YOUR ANSWERS A

Step-by-step explanation:


3 0
3 years ago
Anyone one have the answer to this
OLEGan [10]

Answer: A. y= 5x(x-2)

Step-by-step explanation:

To begin with, this graph has two X values, making it a parabola

Parabola's are NOT linear.

4 0
3 years ago
Consider the following binomial experiment. The probability that a green jelly bean is chosen at random from a large package of
Flura [38]

Answer:

There is a 5.79% probability that at most 2 jelly beans are chosen.

Step-by-step explanation:

For each jelly bean chosen, there are only two possible outcomes. Either it is green, or it is not. This is why we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

There are 13 jelly beans, so n = 13.

The probability that a green jelly bean is chosen at random from a large package of jelly beans is 2/5. This means that p = 0.4.

If Sally chooses 13 jelly beans, what is the probability that at most two will be green jelly beans?

This is

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2).

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{13,0}.(0.4)^{0}.(0.6)^{13} = 0.0013

P(X = 1) = C_{13,1}.(0.4)^{1}.(0.6)^{12} = 0.0113

P(X = 1) = C_{13,2}.(0.4)^{2}.(0.6)^{111} = 0.0453

So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0013 + 0.0113 + 0.0453 = 0.0579.

There is a 5.79% probability that at most 2 jelly beans are chosen.

8 0
3 years ago
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