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Nookie1986 [14]
3 years ago
8

Graph the following equation y = 2/3x

Mathematics
1 answer:
Oxana [17]3 years ago
7 0

Any equation in the form

y=mx

Is a line. So, we only need to sample two points, and then connect them.

If we choose, for example, x=0 and x=3, we have

x=0\implies y=\dfrac{2}{3}\cdot 0 = 0,\quad x=3\implies y=\dfrac{2}{3}\cdot 3 = 2

So, when x=0 then y=0, i.e. the line passes through the origin (0,0).

Similarly, when x=3 then y=2, i.e. the line passes through the point (3,2).

Connect these two points and you have the line.

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Marcy has $20 she wants to buy a book that is marked down 30% from its original price of $28. If the sales tax is 2.5 does she h
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no

Step-by-step explanation:

thirty percent of $28 is $8.4, so you would subtract the two leaving you with $19.6

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5 0
3 years ago
Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.
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Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

f(z_n)={z_{n-1}} ^2+c

Given that:

\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i

The first iterate will be:

\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}

The second iterate will be:

\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}

And the third iterate will be:

\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}

Hence, our answer is C.

3 0
3 years ago
Find the value of trigonometric ratio​
Nana76 [90]

Answer:

We know that Sin,

 =\frac{perpendicular}{hypotenuse}

SinA=\frac{BC}{AC}

SinA=\frac{9}{41}

<u>OAmalOHopeO</u>

7 0
3 years ago
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