What is the slope of the line that passes through the points (48, 10) and (-36, 17)?

Mathematics

1 answer:

schepotkina [342]2 years ago

4 0

Answer:

y = m x + b equation of a straight line

m = (y2 - y1) / (x2 - x1) slope of line

m = (17 - 10) / (-36 - 48) = 7 / -84 = -1 / 12

y = -x / 12 + b equation of line

Or b = y + x / 12

If y = 10 and x = 48 then b = 10 + 48 / 4 = 14

if y = 17 and x = -36 then b = 17 - 36 / 12 = 14

So b = 14 and y = -x / 12 + 14

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Question 1

Galina-37 [17]

Answer:

Did you find the answer???

5 0

2 years ago

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

A square has an area of 148.84m2.<br> Work out the perimeter of the square

Lemur [1.5K]

Answer:

48.8m

Step-by-step explanation:

Formula for square area = $a^{2}$ = 148.84 $m^{2}$