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3 years ago

What is the answer to this

Mathematics

1 answer:

ANEK [815]3 years ago

5 0

To make a large batch of cinnamon rolls, the baker uses 12 cups of white flour and 10 cups of whole wheat flour. All together, he uses 176 ounces of flour. The baker uses 2 fewer cups of whole wheat flour than white flour.

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Find x in the image above

kobusy [5.1K]

Answer:

i would say be smart and actually circle the x but i actually think its the smaller triangle

Step-by-step explanation:

5 0

2 years ago

What is the probability of getting either a nine or an ace when drawing a single card from a deck of 52 cards?

Flura [38]

probability of drawing ace: 4/52 = 1/13

probability of drawing 9: 4/52 = 1/13

probability of drawing ace or 9: 1/13 + 1/13 = 2/13 or ~15.4%

8 0

2 years ago

What is the value of 3b when b = 18?

lubasha [3.4K]

Answer:

Step-by-step explanation:

to evaluate substitute b = 18 into 3b

3b = 3 × 18 = 54

4 0

3 years ago

Read 2 more answers

What is the value of x?<br> 10<br> 2x

Viktor [21]

Answer:

The only way of getting to 10 using 2x it should mean that x = 5

2 * 5 = 10

4 0

3 years ago

Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa

barxatty [35]

$z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}$

We're given that $f_x(6,1)=3$ and $f_y(6,1)=-1$ , and want to find $\frac{\partial z}{\partial v}(1,2)$ .

By the chain rule, we have

$\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}$

and

$\dfrac{\partial x}{\partial v}=2v$

$\dfrac{\partial y}{\partial v}=-1$

Then

$\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)$

(because the point $(x,y)=(6,1)$ corresponds to $(u,v)=(1,2)$ )

$\implies\dfrac{\partial z}{\partial v}(1,2)=3\cdot2\cdot2+(-1)\cdot(-1)=\boxed{13}$

4 0

3 years ago