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11111nata11111 [884]

3 years ago

10

PLEASE HELP ME SOLVE THIS QUESTION ASAPPPPPPPPPPP

1 answer:

AveGali [126]3 years ago

8 0

Answer:

Step-by-step explanation:

Volume of the pyramid :

$V=\dfrac{x^2*h}{3} =554.9\\\\x^2*h=554.9*3\\\\h=15.1\\\\x^2*15.1=554.9*3\\\\x^2=\dfrac{554.9*3}{15.1} \\\\x=\sqrt{\dfrac{1664,7}{15.1} } \\\\x=\sqrt{110,24503311258278145695364238411...} \\\\x=10,499763478887644993681148554978...\approx{10.50}$

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How do u graph y=-4x+2 y=x-3

vlada-n [284]

Answer:

Step-by-step explanation:

7 0

3 years ago

Order from least to greatest. -1/5,1/7,-0.5,1/8

Ivenika [448]

There ya go, Hope, this helps

5 0

4 years ago

I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

so

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$

therefore

$x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

$x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2)

in this problem we have

$x^{2} -6x+4=0$

so

$a=1\\b=-6\\c=4$

substitute in the formula

$x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}$

$x=\frac{6(+/-)\sqrt{20}} {2}$

$x=\frac{6(+/-)2\sqrt{5}} {2}$

$x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}$

$x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}$

therefore

$x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))$

$x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

5 0

3 years ago

The volume of a rectangular box is 2x(2x + 5)(2x – 3). (Drawing is not to scale.)

Anarel [89]

Answer:

Option B. The volume is the product of the area of the base, 2x(2x + 5), and the height, 2x – 3

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

The volume of a rectangular prism is equal to

$V=BH$

where

B is the area of the base of the prism

H is the height of the prism

In this problem we have

The area of the base B is equal to

$B=2x(2x+5)\ units^2$

The height H is equal to

$H=2x-3\ units$

therefore

The volume is equal to

$V=2x(2x+5)(3x-3)\ units^3$

The volume is the product of the area of the base, 2x(2x + 5), and the height, 2x – 3

5 0

3 years ago

.............................................................................

Natasha2012 [34]

There are a lot of dots but do I you have a question

I tried to count them but I kept losing track

8 0

3 years ago