This code attempts to fuse two strings together. So,
fuse("Apple", "Banana")
would return "ABpapnlaen a"
However, there are a couple of things wrong with this code:
- The for loop is incomplete (probably a copy paste error)
- It is unclear from the code if the array jawaban will overflow if kata1 and kata2 are large (it probably will)
- Biggest problem: the jawaban array is declared on the stack, which means it will be cleaned up when the function returns. So the caller of this function will reference unallocated memory! This is a huge bug!!
 
        
             
        
        
        
Answer:
A. 0.0450
B. 4
C. 0.25
D. 37.68
E. 6Hz
F. -0.523
G. 1.5m/s
H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
I. -1.67m/s.
Explanation:
Given the equation:
y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523) 
Standard wave equation:
y(x, t)=Asin(kx−ωt+ϕ)
a.) Amplitude = 0.0450
b.) Wave number = 1/ λ
λ=2π/k
From the equation k = 25.12
Wavelength(λ ) = 2π/25.12 = 0.25 
Wave number (1/0.25) = 4
c.) Wavelength(λ ) = 2π/25.12 = 0.25
d.) Angular frequency(ω)
ωt = 37.68t
ω = 37.68
E.) Frequency (f)
ω = 2πf
f = ω/2π
f = 37.68/6.28
f = 6Hz
f.) Phase angle(ϕ) = -0.523
g.) Wave propagation speed :
ω/k=37.68/25.12=1.5m/s
h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.
 
        
             
        
        
        
I hope this helps but cars, phones and computers.
        
             
        
        
        
Answer:
Flight simulators provide a cost-effective way for pilots to practice both routine and rarely-used skills. With simulator training, you can refine your skills in a variety of different flight scenarios that can be tailored to your specific goals.
Explanation:
hope this helps <3
 
        
                    
             
        
        
        
Answer:
commutative
Explanation:
The commutative property states that the numbers on which we operate can be moved or swapped from their position without making any difference to the answer.