Answer:
The solution code is written in Python 3.
- import random
-
- count = 0
- flag = False
- guess = int(input("Input your guess (2-12): "))
-
- while(count <=3):
- dice1 = random.randint(1, 7)
- dice2 = random.randint(1, 7)
-
- if((dice1 + dice2) == guess):
- flag = True
-
- count += 1
-
-
- if(flag):
- print("User wins!")
- else:
- print("Computer wins!")
Explanation:
A Random generator is needed for this question and therefore we start by importing Python random class (Line 1)
Next, create one counter variable,<em> count</em>, to ensure there will be only three rolling of the dices (Line 3). We need another variable, <em>flag</em>, to track the status if the two dices equal to the <em>guess</em> number chosen by user (Line 4).
Next, prompt use to input a guess number (Line 5).
Within the while loop, we can use random class method <em>randint() to </em>generate random integer. The arguments 1 and 7 will give one random number ranged from 1 to 6 for <em>dice1</em> and<em> dice2</em>, respectively (Line 8 - 9).
If the total of<em> dice1 + dice2</em> equal to user <em>guess</em>, we turn the<em> flag </em>to <em>True</em>. If not, the <em>flag </em>will remain <em>False</em> after completing entire while loop.
If the <em>flag </em>turned to <em>True</em>, print the message "User Wins!" else print the message ("Computer wins!")
Answer:
D.
Explanation:
Kinetic energy can be defined as an energy possessed by an object or body due to its motion.
Mathematically, kinetic energy is given by the formula;

Where;
- K.E represents kinetic energy measured in Joules.
- M represents mass measured in kilograms.
- V represents velocity measured in metres per seconds square.
Generally, when the final velocity at which a physical object moves is equal to zero (0), then it possess maximum kinetic energy.
Hence, the letter which shows the ball when it has the maximum kinetic energy in the graph attached is D.
Answer:
MIPS Code:
.data
newline: .asciiz "\n" #newline variable
.text
MAINLOOP:
li $v0, 5 #syscall to get user interger and store in $v0
syscall
add $a0, $zero, $v0 #moving the user input to $a0 from $v0
beq $a0, 0, EXIT #branching to EXIT when $a0 is 0
li $v0, 1 #syscall to print integer in $a0
syscall
li $v0, 4 #syscall to print newline
la $a0, newline
syscall
j MAINLOOP #jumping to MAINLOOP
EXIT:
Sample Output:
6
6
7
7
3
3
0