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Natasha_Volkova [10]
3 years ago
13

A family has two cars. The first car gets 25 miles per gallon and the second car gets 15 miles per gallon. In a week the two car

s went 725 miles and consumed 35 gallons of gas. How much gas did each car use?
Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:20 and 15 gallons

Step-by-step explanation:

Given

The first car gets 25 miles per gallon

The second car gets 15 miles per gallon

Two cars consumed 35 Gallons

they went for 725 miles in total

suppose the first car consumes x gallons

so, the second car consumes 35-x gallons of gas

We can write

\Rightarrow 25x+15(35-x)=725\\\Rightarrow 25x-10x=725-525\\\Rightarrow 10x=200\\\Rightarrow x=20

First consumed 20 gallons and second consumed 15 gallons

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600 and 60 I do not know what to do
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3 years ago
Find the percent of change from the first value to the second. 20 ; 80
Lemur [1.5K]

Answer:

Percent Change Formula: [(new - old)/old] * 100

Step-by-step explanation:

New - old

80 - 20 = 60

Difference between new - old divided by old

60/20 = 3

Previous quotient times 100

3*100 = 300

Percent Change is 300%

Check your answer

300% of 20 is 60

20 + 60 = 80

8 0
3 years ago
Read 2 more answers
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
4 years ago
Solve. −3.5=−4.6x−5.1 Enter your answer as a fraction in simplest form in the box.
Law Incorporation [45]

Answer:

<u>x = 8/23</u>

Step-by-step explanation:

<u>Adding 3.5 to each side</u>

  • -3.5 + 3.5 = -4.6x - 5.1 + 3.5
  • -4.6x - 1.6 = 0

<u>Adding 4.6x to each side</u>

  • -4.6x - 1.6 + 4.6x = 0 + 4.6x
  • 4.6x = -1.6

<u>Dividing each side by 4.6</u>

  • 4.6x/4.6 = -1.6/4.6
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2 years ago
HELP!!! Simplify cos^2 0 -1/ 4sin^2 0?
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We need to simpify the given expression. The given expression to us is ,

<u>Given </u><u>Expression</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta }

<u>Using </u><u>Identity</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \red{ sin^2\theta + cos^2\theta = 1}

<u>So </u><u>that</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies - sin^2\theta = cos^2\theta -1

<u>We </u><u>have</u><u> </u><u>:</u><u>-</u><u> </u>

\sf\implies \dfrac{ cos^2\theta -1}{4 \ sin^2\theta } \\\\\sf\implies\dfrac{ - sin^2\theta}{4sin^2\theta}=\boxed{\sf -\dfrac{1}{4}}

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3 years ago
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