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anygoal [31]
2 years ago
15

Help please this is urgent

Mathematics
1 answer:
klasskru [66]2 years ago
5 0

Answer:

Step-by-step explanation:

the least common denominator would be 4/10 and 2/10 but that isn’t an option. none of the answers provided are correct. there’s a mistake in the answers.

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Can someone help me I don’t know the answer
user100 [1]

Answer:

P

Step-by-step explanation:

P because it could be anything

And C depends on P

6 0
3 years ago
Can sb answer this correctly plz not a lot so plz do fast thank u
WINSTONCH [101]

Answer:

one

Step-by-step explanation:

4 0
3 years ago
Please help me with these questions
Mars2501 [29]

Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :

\spadesuit\; Slope(m) = \frac{y_1 - y_2}{x_1 - x_2}

Given Points are (8 , 30) and (18 , 60)

here x₁ = 8 and x₂ = 18 and y₁ = 30 and y₂ = 60

\spadesuit\; Slope(m) = \frac{30 - 60}{8 - 18} = \frac{-30}{-10} = 3

We know that the form of line passing through point (x₀ , y₀) and having slope m is : y - y₀ = m(x - x₀)

Here the line passes through the point (8 , 30)

⇒ x₀ = 8 and y₀ = 30

We found Slope(m) = 3

Substituting all the values in the standard form, We get :

Equation of the line : y - 30 = 3(x - 8)

Let d be the x-intercept of this line

⇒ The line passes through the point (d , 0) as at x-intercept, y-coordinate is zero.

⇒ 0 - 30 = 3(d - 8)

⇒ 3d - 24 = -30

⇒ 3d = -30 + 24

⇒ 3d = -6

⇒ d = -2

⇒ The x - coordinate of the x-intercept of the line is -2

6 0
3 years ago
A puppy and kitten are 180 meters apart when they see each other. The puppy can run at a speed of 25 meters per second, while th
Gnom [1K]

It seems it should be the other way... . How soon will the puppy catch up with the kitten.

The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.

If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.

If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.

RT = D kitten

RT = D+180 puppy

20T = D

25T = D + 180

Substitution

25T = 20T +180

5T = 180

T = 36s

7 0
3 years ago
In 2003 a town’s population was 1431. By 2007 the population had grown to 2134. Assume the population is changing linearly.How m
sergiy2304 [10]

We will have the following:

First, we will have that the population change by:

\Delta P=2134-1431\Rightarrow\Delta P=703

So, the population changed by 703 people.

It took the follwoing number of years to change from 1431 to 2134:

\Delta y=2007-2003\Rightarrow\Delta y=4

So, it took 4 years to changes from 1431 to 2134.

m=\frac{2134-1431}{2007-2003}\Rightarrow m=175.75

The average population growth per year is of 175.75 people per year.

The population in 2000 would have been:

P_{2000}=\frac{2000\cdot1431}{2003}\Rightarrow P_{2000}=1428.856715\ldots

\Rightarrow P_{2000}\approx1429

So, the population in 2000 would have been approximately 1429 people.

We will have that the equation for the population would be:

P=(\frac{2134-1431}{2007-2003})t+1429\Rightarrow P=\frac{703}{4}t+1429

So, the equation would be:

P=175.75t+1429

Now, we predict the number of people of the town in 2014:

P_{2014}=175.75(14)+1429\Rightarrow P_{2014}=3889.5

\Rightarrow P_{2014}\approx3890

So, there will be approximately 3890 people of the town in 2014.

3 0
1 year ago
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