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Standard Form is ax + by = c, where a, b, and c are not fractions and a is not negative.
So, you can go through each of your options to see which ones work with those rules.
A. 2.5x + 3y = 12 No, this is not in Standard Form. 2.5 can be rewritten as 2<span>
, menaing A is a fraction, which you can't have.
B. -10x - 3y = 1 No, this is not in Standard Form. A is -10, but A can't be negative.
C. 2x + 3y = 12 Yes, this is in Standard Form. It follows all of the rules.
D. 5x + 5y = 10 Yes, this is in Standard Form. It follows all of the rules.
So, C and D are both written in Standard Form.
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So, you can go through each of your options to see which ones work with those rules.
A. 2.5x + 3y = 12 No, this is not in Standard Form. 2.5 can be rewritten as 2<span>
B. -10x - 3y = 1 No, this is not in Standard Form. A is -10, but A can't be negative.
C. 2x + 3y = 12 Yes, this is in Standard Form. It follows all of the rules.
D. 5x + 5y = 10 Yes, this is in Standard Form. It follows all of the rules.
So, C and D are both written in Standard Form.
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Answer:
b = 7, c = -44
Step-by-step explanation:
If the quadratic equation has the solutions -11 and 4, the two factors are:
Since when we use the zero factor property we get
x+11=0 ⇒ x= -11
x-4=0 ⇒ x=4
Thus, we have used the zero factor property in reverse to find the factorization of the quadratic equation.
Now we develop the multiplications between parenthesis:
So b is the number that accompanies the x: b = 7
and c is the independent number: c = -44
Answer: a. 0.1031; fail to reject the null hypothesis
Step-by-step explanation:
Given: Significance level :
The test statistic in a two-tailed test is z = -1.63.
The P-value for two-tailed test : [By p-value table]
Since, 0.1031 > 0.05
i.e. p-value >
So, we fail to reject the null hypothesis. [When p< then we reject null hypothesis ]
So, the correct option is a. 0.1031; fail to reject the null hypothesis.