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3 years ago

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Mathematics

1 answer:

vitfil [10]3 years ago

8 0

Answer:

A.{-6,3}

Step-by-step explanation:

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Kimberly needs to solve the quadratic equation: x^2 + x – 2 = 2. which statement about how kimberly should solve this equation i

igor_vitrenko [27]

B.The quadratic formula is a good method because this quadratic equation cannot be easily factored.

you just have to get 2 over to the left side of the equation.

4 0

3 years ago

Read 2 more answers

The sides of a triangle have lengths of x, x + 4, and 20. If the longest side is 20, which of the following values of x would ma

GuDViN [60]

Answer:

12<x<16

Step-by-step explanation:

if c^2 > a^2 + b^2

then the triangle is obtuse

since 20 is the longest side

20^2 > x^2 + (x+4)^2

simplify

400 > x^2 + (x+4)(x+4)

FOIL

400 > (x^2 ) + (x^2 + 4x+4x+16)

combine like terms

400 > (2x^2 + 8x+16)

divide by 2

400/2 > 2x^2 /2 + 8x/2 + 16/2

200 > x^2 + 4x +8

subtract 200 from each side

0> x^2 + 4x +8-200

0> x^2 +4x-192

Factor

0 > (x-12) ( x+16)

using the zero product property

0> x-12 0 > x+16

12>x -16>x

x must be greater than 12

we know the longest side is 20

x+4 < 20

subtract 4

x< 16

x>12 and x < 16

12<x<16

5 0

3 years ago

Two different samples will be taken from the same population of test scores where the population mean and standard deviation are

Alenkinab [10]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - α)% confidence interval for population mean μ is:

$\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}$

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (n).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

n₁ = 25

n₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

Width for n = 25:

$\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]$