Answer:
what is the question?
Step-by-step explanation:
8 ^ (-2) = 1 / 64
<span>4 ^ (-3) = 1 / 64</span>
Answer
(C) y +5 =3(x+4)
We will use the point-slope formula to solve this problem.
We will use the point-slope formula to solve this problem.(y+5)=3(x+4)
)Explanation:
)Explanation:We can use the point slope formula to solve this problem.
)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)
)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.
)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.We can substitute the slope and point we were given into this formula to produce the equation we are looking for:
)Explanation:We can use the point slope formula to solve this problem.The point-slope formula states: (y−y1)=m(x−x1)Where m is the slope and (x1y1) is a point the line passes through.We can substitute the slope and point we were given into this formula to produce the equation we are looking for:(y−(−5))=3(x--(4))
=> (<u>y+</u><u>5</u><u>)=3(x</u><u>+</u><u>4</u><u>)</u>
The two points are (x, f(x)) and (x+h, f(x+h)). To find the slope, the definition is the change in y over the change of x. Does this sound familiar!! Applying this definition we get the following formula: and the points x<span>1 = 2 and x2 = 4. Then in our general answer, we will replace x with x1 and h = x2 - x1. Replacing these values in the formula yields 2(2) + (4 - 2) = 4 + 2 = 6. Thus, the slope of the secant line connecting the two points of the function is 6. </span><span>Now using the same function as above, find the average rate of change between x1 = -1 and x2<span> = -3. The answer is 2(-1) + ( -3 + 1) = -2 + -2 = -4. This means that the secant line is going downhill or decreasing as you look at it from le</span></span>