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77julia77 [94]
3 years ago
10

What is the answer to the question above?

Mathematics
2 answers:
serious [3.7K]3 years ago
8 0
B is the option because 6/8 = 3/4
Bond [772]3 years ago
4 0

Answer:

i beleive that B is the best option

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a triangle has two sides of length 6 and 3. what is the smallest possible whole number length for the third side?
svp [43]
Answer: 3
Explanation:
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X^2- 4x- 6y- 14=0 in standard parabola form.
uranmaximum [27]
<span>X^2- 4x- 6y- 14=0
6y = x^2 - 4x - 14 
Divide through by 6:-

y = (1/6)x^2 - (2/3)x -  7/3</span>
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Neporo4naja [7]

Answer:

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Step-by-step explanation:


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The bacteria in an old piece of cheese is growing at a rate that can be modeled by y = 280 • 2^x. Determine which number represe
Katyanochek1 [597]
The answer is <span>C.) 2

The general form of formula is
y = a </span><span>• r^x
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x - period of time

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<span>y = 280 • 2^x

Since r = 2, the growth rate is C.) 2</span>
5 0
4 years ago
Read 2 more answers
Sqaure root of 5 (u-1)(u^5+u^4+u^3+u^2+u+1)
Anna71 [15]
GIVEN:

5(u - 1)( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1)

remember:

\sqrt{u} = {u}^{ \frac{1}{2} }

And

{u}^{n} \times {u}^{m} = {u}^{n + m}

SOLVE:

start by multiplying the factors:

5( ({u}^{6} + {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u ) - ( {u}^{5} + {u}^{4} + {u}^{3} + {u}^{2} + u + 1))

simplify by combing like terms. Most terms subtract off, leaving:

5( {u}^{6} - 1)

This can be factored, but it is not a perfect square, which is really what we need to take the square root.

5( {u}^{3} - 1)( {u}^{3} + 1)

I'm not exactly sure what form they want the answer in...

so taking the square root:

\sqrt{5( {u}^{6} - 1) } = {(5( {u}^{6} - 1))}^{ \frac{1}{2} }

so my best answer is:

{5}^{ \frac{1}{2} } \times {( {u}^{6} - 1)}^{ \frac{1}{2} }
or the more factored form:

{5}^{ \frac{1}{2} } { ({u}^{3} - 1)}^{ \frac{1}{2} } { ({u}^{3} + 1 )}^{ \frac{1}{2} }

I'm not sure how else to solve it. Taking the square root doesn't work out super well, so I left it in the most simple form I could.

sorry for not coming to a definitive answer!
7 0
3 years ago
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