For a function p(x), as — then p(x) — 4. Which of the following graphs<br> could be p(x)?

The flower shop sold roses and tulips. The number of roses sold was 5 less than twice the number of tulips sold. If the shop sol

LenaWriter [7]

Answer: the number of roses sold is 69 while number of tulips is 37

Step-by-step explanation:

Let x represent the number of roses that the flower shop sold.

Let y represent the number of tulips that the flower shop sold.

The number of roses sold was 5 less than twice the number of tulips sold. This means that

x = 2y - 5 - - -- -- - - - - - ;1

If the shop sold 106 flowers in total, it means that

x + y = 106

Substituting x = 106 - y into equation 1, it becomes

106 - y = 2y - 5

3y = 106 + 5 = 111

y = 111/3 = 37

x = 106 - y = 106 - 37

x = 69

7 0

3 years ago

Hi, I need an answer to this question pls. Louisa used Uber which charges $2 for the first mile and $1.10 for each additional mi

Vanyuwa [196]

Answer:

20 miles

Step-by-step explanation:

Let x = amount charge each mile

y = total price paid

Since the Uber charged $1.10 for each mile, we multiply x by 1.1 like this 1.1x

Also, $2 were already charged so we add 2 to the total price

y = 1.1x + 2

Since the Lyft charged $0.95 for each mile, we multiply x by 0.95 like this 0.95x

Also, $5 were arleady charged so we add 5 to the total price

y = 0.95x + 5

We have to find a price where both rides match

1.1x + 2 = 0.95x + 5

Let's move the like terms to one side by subtracting 0.95x from both sides

1.1x + 2 = 0.95x + 5

-0.95x -0.95x

0.15x + 2 = 5

Now, subtract 2 from both sides

0.15x + 2 = 5

- 2 - 2

0.15x = 3

Finally, divide both sides by the coefficient, 0.15, to isolate the variable, x

0.15x/0.15 = 3/0.15

x = 20

This means they traveled 20 miles if they were to pay the same price

7 0

3 years ago

Last year, Megan earned £158900 before tax

ladessa [460]

What’s the question?

6 0

3 years ago

A customer went to a garden shop and bought some potting soil for $11.50 and 9 shrubs. The total bill was $94.75. Write and solv

Vladimir79 [104]

Hey there,

Your question states: <span>A customer went to a garden shop and bought some potting soil for $11.50 and 9 shrubs. The total bill was $94.75. Write and solve an equation to find the price of each shrub.

So, I will do 94.75 minus 11.50 because he bought nice scrubs so that would be 83.25.

I will do 83.25 divided by 9 because that's the number that person bought, each scrub will end up to be 9.25.

Hope this helps.

~Jurgen</span>

6 0

3 years ago

Read 2 more answers

A carnival charges two different prices for admissions. Adults cost $4 while children cost $1.50. If a total of $5050 was collec

GenaCL600 [577]

Answer:

Step-by-step explanation:

We have to have 2 different equations to solve this. One equation will represent the number of tickets sold while the other represents the money collected when the tickets were sold.

We know that adult tickets + children tickets = 2200 tickets.

That's the "number of tickets" equation. Let's call adult tickets "a" and children's tickets "c". So a + c = 2200

Now if each adult costs $4, then the expression that represents that as a cost is 4a. If there is 1 adult, the cost is $4(1) = $4; if there are 2 adults, the cost is $4(2) = $8; if there are 3 adults, the cost is $4(3) = $12, etc.

The same goes for the children's tickets. If each child's ticket is $1.50, then the expression that represents the cost of a child's ticket is 1.5c (we don't need the 0 at the end; it doesn't change anything to drop it off). The total money brought in from the cost of these tickets was $5050, so

4a + 1.5c = 5050

Let's solve the first equation for a. If a + c = 2200, then a = 2200 - c. Sub that into the second equation and solve it for c:

4(2200 - c) + 1.5c = 5050 and

8800 - 4c + 1.5c = 5050 and

-2.5c = -3750 so

c = 1500

That means that there were 1500 children's tickets sold. If a + c = 2200, then a + 1500 = 2200 so

a = 2200 - 1500 so

a = 700

There were 1500 children's tickets sold and 700 adult tickets sold.

7 0

3 years ago

For a function p(x), as — then p(x) — 4. Which of the following graphs could be p(x)?