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vlabodo [156]
4 years ago
11

Find the additive inverse of 18/23

Mathematics
2 answers:
AVprozaik [17]4 years ago
7 0
\frac ab\  inverse\ is\ \frac ba\\
\\
\frac{18}{23} =>\frac{23}{18}=1\frac5{18}
MissTica4 years ago
6 0

Answer:

.078260869565

Step-by-step explanation:

Simply and THINK HARD

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6 pounds of shrimp for 18.06 what is the unit price
frosja888 [35]
The answer is $3.01. To get this answer, divide 18.06 by 6. This is the unit price. 18.6/6. I hope this helps and I hope you have a blessed day.
6 0
3 years ago
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Brian has to send 13 parcels it will be cheaper to send the parcels by the express service than by the rapid service. ​
Arte-miy333 [17]

Answer: £ 260.78

Step-by-step explanation:

4 0
4 years ago
Simplify and determine the coefficient of (-2/5x)(5y)(-2x).
Juli2301 [7.4K]
Solution/Answer : 4

Solution: the first you do is multiply the last two parentheses to get -10xy


Now we are left with ( -2/5x)(-10xy)
Then we multiply that out into
(-2*-10)/5*x^2y = 20/5x^2y =
4x^2y

The coefficient in this case would be four. (In case you were confused about what a coefficient actually is, it’s the number you multiply a variable by)

Hopes this helps :)

4 0
2 years ago
If the side that is 6 units long is the base of this parallelogram, what is its corresponding height.
zmey [24]

Answer:

4 units.

Step-by-step explanation:

No matter which side is chosen as the base, the area of the parallelogram is the product of that base and its corresponding height. With this we are trying to get 24 as area. So, since 6 units x 4 units = 24 units.

Thus, We can say the base is 6 units and height is 4 units.

6 0
3 years ago
Element X decays radioactively with a half life of 11 minutes. If there are 870 grams of Element X, how long, to the nearest ten
serg [7]

Answer:

It would take 27.5 minutes the element to decay to 154 grams.

Step-by-step explanation:

The decay equation:

\frac {dN}{dt}\propto -N

\Rightarrow \R\frac {dN}{dt}=-\lambda N

\Rightarrow \frac {dN}N=-\lambda  dt

Integrating both sides

\Rightarrow \int \frac {dN}N=\int-\lambda  dt

\Rightarrow ln|N|=-\lambda  t+c

When t=0, N=N_0 = initial amount

ln|N_0|=-\lambda  .0+c

\Rightarrow c=ln|N_0|

ln|N|=-\lambda t+ln|N_0|

\Rightarrow ln|N|-ln|N_0|=-\lambda t

\Rightarrow ln|\frac{N}{N_0}|=-\lambda t

Decay equation:              

                    ln|\frac{N}{N_0}|=-\lambda t

Given that, the half life of of element X is 11 minutes.

For half life, N=\frac12  N_0,  t= 11 min.

ln|\frac{N}{N_0}|=-\lambda t

\Rightarrow ln|\frac{\frac12N_0}{N_0}|=-\lambda . 11

\Rightarrow ln|\frac12}|=-\lambda . 11

\Rightarrow -\lambda . 11=ln|\frac12}|

\Rightarrow \lambda =\frac{ln|\frac12|}{-11}

\Rightarrow \lambda =\frac{ln|2|}{11}                [ ln|\frac12|=ln|1|-ln|2|=-ln|2| , since ln|1|=0]

N=154 grams, N_0 = 870 grams, t=?

ln|\frac{N}{N_0}|=-\lambda t

\Rightarrow ln|\frac{154}{870}|=-\frac{ln|2|}{11}.t

\Rightarrow t= \frac{ln|\frac{154}{870}|\times 11}{-ln|2|}

      =27.5 minutes

It would take 27.5 minutes the element to decay to 154 grams.

5 0
3 years ago
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